摘要: We know that$$\tan t=\frac{e^{it}-e^{-it}}{i(e^{it}+e^{-it})}=\frac{e^{2i t}+1-2}{i(e^{2it}+1)}=-i(1-\frac{2}{e^{2it}+1}).$$Now we try to find the ant... 阅读全文
posted @ 2013-09-25 21:12 叶卢庆 阅读(196) 评论(0) 推荐(0) 编辑