计算u8中位1的个数

unsigned char count_ones(unsigned char n)
{
n = (n & 0x55) + ((n >> 1) & 0x55);
n = (n & 0x33) + ((n >> 2) & 0x33);
return (n + (n >> 4)) & 0x0F;
}

 

posted @ 2025-06-25 18:18  =没有编程天赋=  阅读(3)  评论(0)    收藏  举报