发送get请求报错， Exception in thread "main" java.lang.IllegalArgumentException: Illegal character in query at index 103

处理url,发送get请求时报错；

解决方法：利用 URLEncoder.encode("参数","UTF-8");方法对参数进行转化

String paramAfter = URLEncoder.encode("参数","UTF-8");
然后再将 paramAfter  拼接到url里面；

 url += "&" + key + "=" + paramAfter；

原因：

 

例子：

    public static String doGet(String params, String url) throws UnsupportedEncodingException {
        String result="";
        if(params!=null && params.length()>0){
            // 》0说明有参数
            Map<String,Object> paramMap= (Map<String, Object>) JSONObject.parse(params);
            int target = 1;
            for(String key : paramMap.keySet()){
                // 判断是否为第一个参数
                if (target == 1) {
                    url += "?" + key + "=" +  URLEncoder.encode((paramMap.get(key)).toString(),"UTF-8");
                } else {

                    url += "&" + key + "=" + URLEncoder.encode((paramMap.get(key)).toString(),"UTF-8");

                }
                target++;
            }
        }
        try{

            HttpGet get = new HttpGet(url);


            //        设置请求超时时间
            RequestConfig requestConfig = RequestConfig.custom().setConnectTimeout(3000)
                    .setConnectionRequestTimeout(3000)
                    .setSocketTimeout(3000)
                    .build();
            get.setConfig(requestConfig);

            // 添加token
            addTokenInRequest(get);

            CloseableHttpResponse httpResponse = trustAll().execute(get);
            //返回结果
            int statusCode = httpResponse.getStatusLine().getStatusCode();
            String postReturn = EntityUtils.toString(httpResponse.getEntity());
            result = "code=" + statusCode + ",result = " + postReturn;
        }catch (IOException  e){
            e.printStackTrace();
        }
        return result;
    }