gin框架实现一个简单的项目 ③

承接:gin框架封装自己的路由 ②

对于一个项目来说,需要将各个功能模块分开,也就是所谓的三层模型,这里介绍一下个人的做法:

contorller主要负责路由

model主要负责程序输入输出的数据

service主要负责数据处理

utils主要负责存放通用的方法,比如连接数据库

代码如下:

project->index.go

package main

import (
    c "project/controller"

    "github.com/gin-gonic/gin"
)

func main() {
    r := gin.Default()
    rr := c.GinRouter(r)

    // 监听并在 0.0.0.0:8080 上启动服务
    rr.Run(":8080")
}
View Code

project->controller->index.go

package controller

import (
    "fmt"
    "project/controller/second"

    "github.com/gin-gonic/gin"
)

func GinRouter(r *gin.Engine) *gin.Engine {
    rr := r.Group("/")
    rr.GET("/first", func(c *gin.Context) {
        fmt.Println("first .........")
    })
    rr = r.Group("/a")
    second.Routers(rr)
    return r
}
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project->controller->second->index.go

package second

import (
    "fmt"
    ms "project/model/second"
    ss "project/services/second"

    "github.com/gin-gonic/gin"
)

func Routers(r *gin.RouterGroup) {
    rr := r.Group("")
    rr.POST("/second", Function)
    return
}
func Function(c *gin.Context) {
    var input ms.Input
    if err := c.BindJSON(&input); err != nil {
        fmt.Println(err)
    }
    ss.Function(c, input)
    return
}
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project->model->second->index.go

package second

type Input struct {
    Id int `view:"id号" json:"id" from:"id"`
}
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project->services->second->index.go

package second

import (
    "fmt"
    ms "project/model/second"

    "github.com/gin-gonic/gin"
)

func Function(c *gin.Context, input ms.Input) {
    fmt.Println("second .........,input:", input.Id)
    return
}
View Code

 

posted @ 2019-11-22 12:44  ybf&yyj  阅读(1931)  评论(0编辑  收藏  举报