leetcode324 Wiggle Sort II 

 1 """
 2 Given an unsorted array nums, reorder it such that nums[0] < nums[1] > nums[2] < nums[3]....
 3 Example 1:
 4 Input: nums = [1, 5, 1, 1, 6, 4]
 5 Output: One possible answer is [1, 4, 1, 5, 1, 6].
 6 Example 2:
 7 Input: nums = [1, 3, 2, 2, 3, 1]
 8 Output: One possible answer is [2, 3, 1, 3, 1, 2].
 9 """
10 """
11 先排序，再折半拆成两个子数组，再归并
12 但本题的关键是需要对两个子数组由后向前取元素
13 """
14 class Solution:
15     def wiggleSort(self, nums):
16         """
17         Do not return anything, modify nums in-place instead.
18         """
19         l = sorted(nums)
20         mid = (len(l)+1)//2
21         l1 = l[:mid]
22         l2 = l[mid:]
23         k, i, j = 0, len(l1)-1, len(l2)-1 #!!!逆着合并 测试[4, 5, 5, 6]
24         while i >= 0 or j >= 0: #bug 写成了i>0
25             if i >= 0:
26                 nums[k] = l1[i]
27                 i -= 1
28                 k += 1
29             if j >= 0:
30                 nums[k] = l2[j]
31                 j -= 1
32                 k += 1
33 if __name__ == '__main__':
34     nums = [1,3,2,2,3,1]
35     ans = Solution()
36     res = ans.wiggleSort(nums)

 

posted @ 2020-03-07 00:15  yawenw  阅读(115)  评论(0)    收藏  举报