开发随笔——NOT IN vs NOT EXISTS

原文出处: http://blog.csdn.net/dba_huangzj/article/details/31374037  转载请引用

之前在论坛中见到一个针对in/exists的讨论。原帖懒得找了,这里介绍一下近期的学习小结:

NOT IN和NOT EIXTS在对同意为null的列查询时会有一定的风险。特别是NOT IN,假设子查询包括了最少一个NULL,会出现非预期的结果。以下做一个演示。

 

IF OBJECT_ID('ShipmentItems', 'U') IS NOT NULL 
    DROP TABLE dbo.ShipmentItems; 
GO 
CREATE TABLE dbo.ShipmentItems 
    ( 
      ShipmentBarcode VARCHAR(30) NOT NULL , 
      Description VARCHAR(100) NULL , 
      Barcode VARCHAR(30) NOT NULL 
    ); 
GO 
INSERT  INTO dbo.ShipmentItems 
        ( ShipmentBarcode , 
          Barcode , 
          Description 
        ) 
        SELECT  '123456' , 
                '1010203' , 
                'Some cool widget' 
        UNION ALL 
        SELECT  '123654' , 
                '1010203' , 
                'Some cool widget' 
        UNION ALL 
        SELECT  '123654' , 
                '1010204' , 
                'Some cool stuff for some gadget'; 
GO 
-- retrieve all the items from shipment 123654 
-- that are not shipped in shipment 123456 
SELECT  Barcode 
FROM    dbo.ShipmentItems 
WHERE   ShipmentBarcode = '123654' 
        AND Barcode NOT IN ( SELECT Barcode 
                             FROM   dbo.ShipmentItems 
                             WHERE  ShipmentBarcode = '123456' ); 
/* 
Barcode 
------------------------------ 
1010204
*/


 

能够看出得到了期待结果。以下看看改动表结构,同意列为null的情况:

ALTER TABLE dbo.ShipmentItems 
ALTER COLUMN Barcode VARCHAR(30) NULL; 
INSERT  INTO dbo.ShipmentItems 
        ( ShipmentBarcode , 
          Barcode , 
          Description 
        ) 
        SELECT  '123456' , 
                NULL , 
                'Users manual for some gadget'; 
GO 
SELECT  Barcode 
FROM    dbo.ShipmentItems 
WHERE   ShipmentBarcode = '123654' 
        AND Barcode NOT IN ( SELECT Barcode 
                             FROM   dbo.ShipmentItems 
                             WHERE  ShipmentBarcode = '123456' ); 
/* 
Barcode 
------------------------------
*/


非常多人会认为这是一个bug,有时候能查出数据。有时候却不能。可是实际上不是bug,当NOT IN子句返回最少一个NULL时,查询会返回空。以下的语句能更好地说明这个想法:

SELECT  CASE WHEN 1 NOT IN ( 2, 3 ) THEN 'True' 
             ELSE 'Unknown or False' 
        END , 
        CASE WHEN 1 NOT IN ( 2, 3, NULL ) THEN 'True' 
             ELSE 'Unknown or False' 
        END; 
/* 
---- ---------------- 
True Unknown or False 
*/


实际上,因为IN的本质是OR操作,所以:


SELECT  CASE WHEN 1 IN ( 1, 2, NULL ) THEN 'True' 
             ELSE 'Unknown or False' 
        END ;

中,1 in 1。也就是为TRUE,所以返回true。这个语句的逻辑实际上是:

SELECT  CASE WHEN ( 1 = 1 ) 
                  OR ( 1 = 2 ) 
                  OR ( 1 = NULL ) THEN 'True' 
             ELSE 'Unknown or False' 
        END ;
 


当使用NOT IN 时,如以下的语句:

SELECT  CASE WHEN 1 NOT IN ( 1, 2, NULL ) THEN 'True' 
             ELSE 'Unknown or False' 
        END ;


会转变成:

SELECT  CASE WHEN NOT ( ( 1 = 1 ) 
                        OR ( 1 = 2 ) 
                        OR ( 1 = NULL ) 
                      ) THEN 'True' 
             ELSE 'Unknown or False' END ;


依据离散数学的概念,能够转换为:

SELECT  CASE WHEN ( ( 1 <> 1 ) 
                    AND ( 1 <> 2 ) 
                    AND ( 1 <> NULL ) 
                  ) THEN 'True' 
             ELSE 'Unknown or False' 
        END ;


谓词有短路特性,即在AND条件中。仅仅要有一个条件为false,整个条件都为false,而1<>1是为false,所以后面的也不须要推断了,直接返回else部分。即使是1<>null,依据集合论的特性,NULL和实际数据的对照总是返回unknown,所以也是为false。假设你非要用NOT IN 。请确保子查询永远不会有NULL返回。或者须要额外处理去除NULL,比方:

SELECT  Barcode 
FROM    dbo.ShipmentItems 
WHERE   ShipmentBarcode = '123654' 
  AND Barcode NOT IN ( SELECT Barcode 
                       FROM   dbo.ShipmentItems 
                       WHERE  ShipmentBarcode = '123456' 
                         AND Barcode IS NOT NULL ) ;


另一种方法就是改写语句,用NOT EXISTS来等价替换:

SELECT  i.Barcode 
FROM    dbo.ShipmentItems AS i 
WHERE   i.ShipmentBarcode = '123654' 
        AND NOT EXISTS ( SELECT * 
                         FROM   dbo.ShipmentItems AS i1 
                         WHERE  i1.ShipmentBarcode = '123456' 
                                AND i1.Barcode = i.Barcode ); 
/* 
Barcode 
------------------------------ 
1010204
*/


另外,基于SARG要求,一般不建议用NOT IN/NOT EXISTS这样的反向扫描,避免影响性能。另一个选择使用IN/EXISTS的要点。就是多列匹配的问题,在T-SQL中,多列同一时候匹配要用EXISTS,而单列匹配能够用EXISTS/IN。可能能够用其它写法来实现IN的多列匹配,可是一般我个人会选择使用EXISTS来匹配多列。


原文出自:CSDN博客:黄钊吉的博客

posted @ 2017-06-07 16:41  yangykaifa  阅读(141)  评论(0编辑  收藏  举报