稀疏数组

public class ArrayDemo08 {
public static void main(String[] args) {
//创建一个二维数组 11*11 0:没有棋子 1:黑棋 2:蓝棋
int[][] array1 = new int[11][11];
array1[1][2] = 1;
array1[2][3] = 2;
//输出原始数组
System.out.println("输出原始数组");

for (int[] ints : array1) {
for (int anInt : ints) {
System.out.print(anInt+"\t");
}
System.out.println();
}
System.out.println("=======================");

//转换为稀疏数组保存
//获取有效值的个数
int sum = 0;
for (int i = 0; i < 11; i++) {
for (int j = 0; j < 11; j++) {
if (array1[i][j]!=0){
sum++;

}
}
}
System.out.println("有效值为"+sum);

//创建一个稀疏数组
int[][] array2 = new int[sum+1][3];
array2[0][0] = 11;
array2[0][1] = 11;
array2[0][2] = sum;

//遍历二维数组,将非零的值,存放稀疏数组中
int count = 0;
for (int i = 0; i < array1.length; i++){
for (int j = 0; j < array1[i].length; j++) {
if (array1[i][j]!=0){
count++;
array2[count][0] = i;
array2[count][1] = j;
array2[count][2] = array1[i][j];

}

}

}
//输出稀疏数组
System.out.println("稀疏数组");
for (int i = 0; i < array2.length; i++) {
System.out.println(array2[i][0]+"\t"
+array2[i][1]+"\t"
+array2[i][2]+"\t");

}
System.out.println("===============");
System.out.println("还原");
//1 读取稀疏数组
int[][] array3 = new int[array2[0][0]][array2[0][1]];

//2 给其中的元素还原他的值
for (int i = 1; i < array2.length; i++) {
array3[array2[i][0]][array2[i][1]] = array2[i][2];

}
//3 打印
System.out.println("输出原始数组");

for (int[] ints : array3) {
for (int anInt : ints) {
System.out.print(anInt+"\t");
}
System.out.println();
}

}
}
posted @ 2022-03-28 16:31  白糖11  阅读(7)  评论(0)    收藏  举报