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模拟n个人参加选举的过程,并输出选举结果:假设候选人有四人,分别用A,B,C,D表示,当选某候选人时,直接输入其编号(编号由计算机随机产生,若输入的不是A,B,C,D则视为无效票,选举结束后按得票数从高到底输出候选人编号和所得票数.

 

 

 1 #import <Foundation/Foundation.h>
 2 
 3 int main(int argc, const char * argv[]) {
 4     
 5     
 6    
 7     int n = 0;
 8     int A = 0,B =0,C = 0,D = 0,abandon = 0;
 9     int ran = 0;
10     printf("请输入参举得人数:");
11     scanf("%d",&n );
12     for (int i = 0; i < n; i++) {
13         ran = arc4random()%(4-1+1)+1+64;
14         switch (ran) {
15             case 'A':
16                 A++;
17                 break;
18             case 'B':
19                 B++;
20                 break;
21             case 'C':
22                 C++;
23                 break;
24             case 'D':
25                 D++;
26                 break;
27                 
28                 
29             default:
30                 abandon++;
31                 break;
32         }
33         
34         
35     }
36     for (int i = 0; i < 4; i++) {
37         if (A >= B && A >= C && A >= D && A != -1) {
38             printf("A的选票是%d\n",A);
39             A = -1;
40         }
41         if (B >= A && B >= C && B >= D && B != -1) {
42             printf("B的选票是%d\n",B);
43             B = -1;
44         }
45         if (C >= A && C >= B && C >= D && C != -1) {
46             printf("C的选票是%d\n",C);
47             C = -1;
48         }
49         if (D >= A && D >= B && D >= C && D != -1) {
50             printf("D的选票是%d\n",D);
51             D = -1;
52         }
53             
54     }
55     
56     return 0;
57 }

 

 

 

posted on 2015-11-30 20:04  阳Sea  阅读(2187)  评论(0)    收藏  举报