iOS判断字符串是否包含表情字符 

 1 - (BOOL)isContainsEmoji:(NSString *)string {
 2     __block BOOL isEomji = NO;
 3     [string enumerateSubstringsInRange:NSMakeRange(0, [string length]) options:NSStringEnumerationByComposedCharacterSequences usingBlock:
 4      ^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop) {
 5          const unichar hs = [substring characterAtIndex:0];
 6          if (0xd800 <= hs && hs <= 0xdbff) {
 7              if (substring.length > 1) {
 8                  const unichar ls = [substring characterAtIndex:1];
 9                  const int uc = ((hs - 0xd800) * 0x400) + (ls - 0xdc00) + 0x10000;
10                  if (0x1d000 <= uc && uc <= 0x1f77f) {
11                      isEomji = YES;
12                  }
13              }
14          } else if (substring.length > 1) {
15              const unichar ls = [substring characterAtIndex:1];
16              if (ls == 0x20e3 || ls == 0xfe0f) {
17                  isEomji = YES;
18              }
19          } else {
20              if (0x2100 <= hs && hs <= 0x27ff && hs != 0x263b) {
21                  isEomji = YES;
22              } else if (0x2B05 <= hs && hs <= 0x2b07) {
23                  isEomji = YES;
24              } else if (0x2934 <= hs && hs <= 0x2935) {
25                  isEomji = YES;
26              } else if (0x3297 <= hs && hs <= 0x3299) {
27                  isEomji = YES;
28              } else if (hs == 0xa9 || hs == 0xae || hs == 0x303d || hs == 0x3030 || hs == 0x2b55 || hs == 0x2b1c || hs == 0x2b1b || hs == 0x2b50|| hs == 0x231a ) {
29                  isEomji = YES;
30              }
31          }
32      }];
33     return isEomji;
34 }

 

posted @ 2014-11-26 09:27  回读(IOS)  阅读(1535)  评论(0)    收藏  举报