Struts1入门实例(简单登录)

现在开始加入公司的核心项目,但由于项目开发比较早,所以使用的技术不是很新潮,前台用的还是struts1。

虽然不是什么新技术,但仍可以从中学到好多东西的。花了一个晚上的时间终于把struts1的流程跑通了。

省略了创建过程及加入jar包的过程,直接进入正题。

首页要在web.xml中添加相应的struts配置:

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<servlet>
        <servlet-name>action</servlet-name>
        <servlet-class>
            org.apache.struts.action.ActionServlet
        </servlet-class>
        <init-param>
            <param-name>config</param-name>
            <param-value>/WEB-INF/struts-config.xml</param-value>
        </init-param>
        <init-param>
            <param-name>debug</param-name>
            <param-value>2</param-value>
        </init-param>
        <init-param>
            <param-name>detail</param-name>
            <param-value>2</param-value>
        </init-param>
        <load-on-startup>2</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>action</servlet-name>
        <url-pattern>*.do</url-pattern>
    </servlet-mapping>
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然后在config所对应的目录下添加struts配置文件struts-config.xml

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<?xml version="1.0" encoding="UTF-8" ?>

<!DOCTYPE struts-config PUBLIC
          "-//Apache Software Foundation//DTD Struts Configuration 1.2//EN"
          "http://jakarta.apache.org/struts/dtds/struts-config_1_2.dtd">

<struts-config>

<!-- ActionForm  -->
    <form-beans>
    <!-- name:名称 type:类路径 -->
        <form-bean name="loginForm" type="com.login.LoginForm">
        </form-bean>
    </form-beans>
<!-- 设置全局URL,必须写在Action前面,这样任何Action都可以使用 -->
    <global-forwards>
        <forward name="result" path="/result.jsp" />
    </global-forwards>

<!-- 注册Action -->
    <action-mappings>
    <!-- name:名称 type:类路径 path:客户端(JSP)提交到服务器端时指定的路径(Form表单中的action=”/login.do" -->
        <action path="/login" type="com.login.LoginAction"
            name="loginForm" scope="request">
            <!-- 局部URL,只有这个action可以使用 -->
            <forward name="success" path="/success.jsp"></forward>
            <forward name="error" path="/error.jsp"></forward>
        </action>
    </action-mappings>


</struts-config>
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注:Action和Form的关系是一个Action只能对应一个Form(通过Action的name属性)
而一个Form可以被多个Action调用
LoginAction.java
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package com.login;

import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.apache.struts.action.Action;
import org.apache.struts.action.ActionForm;
import org.apache.struts.action.ActionForward;
import org.apache.struts.action.ActionMapping;

public class LoginAction extends Action {

    @Override
    public ActionForward execute(ActionMapping mapping, ActionForm form,
            HttpServletRequest request, HttpServletResponse response)
            throws Exception {
        LoginForm lf = (LoginForm) form;
        String username = lf.getUsername();
        String password = lf.getPassword();
        String errorInfo = "";
        String result = UserManager.getInstance().login(username, password);
        if (result.equals("success")) {
            request.setAttribute("username", username);
            return mapping.findForward("success");
        } else if (result.equals("username")) {
            errorInfo = "密码错误";
        } else {
            errorInfo = "用户名错误";
        }
        request.setAttribute("errorInfo", errorInfo);
        return mapping.findForward("error");
    }

}
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LoginForm.java
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package com.login;

import javax.servlet.http.HttpServletRequest;

import org.apache.struts.action.ActionErrors;
import org.apache.struts.action.ActionForm;
import org.apache.struts.action.ActionMapping;

public class LoginForm extends ActionForm {

    private String username;
    private String password;

    public void reset(ActionMapping mapping, HttpServletRequest request) {
        System.out.println("--------reset()-------------");
        super.reset(mapping, request);
    }

    public ActionErrors validate(ActionMapping mapping,
            HttpServletRequest request) {
        System.out.println("--------validate()-------------");
        return super.validate(mapping, request);
    }

    public String getUsername() {
        return username;
    }

    public void setUsername(String username) {
        this.username = username;
    }

    public String getPassword() {
        return password;
    }

    public void setPassword(String password) {
        this.password = password;
    }

}
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对我个人来说最重要的是前台jsp页面没有掌握,经常在页面上花费很多时间
在编写JSP页面时要用struts标签,而我经常会忘记
引入jsp标签
<%@ taglib uri="http://struts.apache.org/tags-html" prefix="html" %>
<%@ taglib uri="http://struts.apache.org/tags-bean" prefix="bean" %>
index.jsp
<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%>
<%@ taglib uri="http://struts.apache.org/tags-html" prefix="html" %>
<%@ taglib uri="http://struts.apache.org/tags-bean" prefix="bean" %>

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
	<head>
		<title>首页</title>
	</head>

	<body>
		<html:form action="/login.do">
			用户名:<html:text property="username"></html:text><br/>
			密码: <html:password property="password"></html:password><br/>
			<html:submit>submit</html:submit>
		</html:form>
	</body>
</html>

 

展示结果(将Action的返回值展示到JSP页面上)

<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%>
<%@ taglib uri="http://struts.apache.org/tags-html" prefix="html"%>
<%@ taglib uri="http://struts.apache.org/tags-bean" prefix="bean"%>

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
	<head>
		<title>Error</title>
	</head>
	<body>
		<bean:write name="errorInfo" scope="request" />
	</body>
</html>
posted @ 2014-08-11 12:00  yangkai_keven  阅读(326)  评论(0编辑  收藏  举报