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金额小写转换为大写

Posted on 2008-04-16 21:35  新人~  阅读(423)  评论(2编辑  收藏  举报
/// <summary> 
        
/// 转换人民币大小金额
        
/// </summary> 
        
/// <param name="num">金额</param> 
        
/// <returns>返回大写形式</returns> 

        public static string CmycurD(decimal num)
        
{
            
string str1 = "零壹贰叁肆伍陆柒捌玖";            //0-9所对应的汉字 
            string str2 = "万仟佰拾亿仟佰拾万仟佰拾元角分"//数字位所对应的汉字 
            string str3 = "";    //从原num值中取出的值 
            string str4 = "";    //数字的字符串形式 
            string str5 = "";  //人民币大写金额形式 
            int i;    //循环变量 
            int j;    //num的值乘以100的字符串长度 
            string ch1 = "";    //数字的汉语读法 
            string ch2 = "";    //数字位的汉字读法 
            int nzero = 0;  //用来计算连续的零值是几个 
            int temp;            //从原num值中取出的值 

            num 
= Math.Round(Math.Abs(num), 2);    //将num取绝对值并四舍五入取2位小数 
            str4 = ((long)(num * 100)).ToString();        //将num乘100并转换成字符串形式 
            j = str4.Length;      //找出最高位 
            if (j > 15return "溢出"; }
            str2 
= str2.Substring(15 - j);   //取出对应位数的str2的值。如:200.55,j为5所以str2=佰拾元角分 

            
//循环取出每一位需要转换的值 
            for (i = 0; i < j; i++)
            
{
                str3 
= str4.Substring(i, 1);          //取出需转换的某一位的值 
                temp = Convert.ToInt32(str3);      //转换为数字 
                if (i != (j - 3&& i != (j - 7&& i != (j - 11&& i != (j - 15))
                
{
                    
//当所取位数不为元、万、亿、万亿上的数字时 
                    if (str3 == "0")
                    
{
                        ch1 
= "";
                        ch2 
= "";
                        nzero 
= nzero + 1;
                    }

                    
else
                    
{
                        
if (str3 != "0" && nzero != 0)
                        
{
                            ch1 
= "" + str1.Substring(temp * 11);
                            ch2 
= str2.Substring(i, 1);
                            nzero 
= 0;
                        }

                        
else
                        
{
                            ch1 
= str1.Substring(temp * 11);
                            ch2 
= str2.Substring(i, 1);
                            nzero 
= 0;
                        }

                    }

                }

                
else
                
{
                    
//该位是万亿,亿,万,元位等关键位 
                    if (str3 != "0" && nzero != 0)
                    
{
                        ch1 
= "" + str1.Substring(temp * 11);
                        ch2 
= str2.Substring(i, 1);
                        nzero 
= 0;
                    }

                    
else
                    
{
                        
if (str3 != "0" && nzero == 0)
                        
{
                            ch1 
= str1.Substring(temp * 11);
                            ch2 
= str2.Substring(i, 1);
                            nzero 
= 0;
                        }

                        
else
                        
{
                            
if (str3 == "0" && nzero >= 3)
                            
{
                                ch1 
= "";
                                ch2 
= "";
                                nzero 
= nzero + 1;
                            }

                            
else
                            
{
                                
if (j >= 11)
                                
{
                                    ch1 
= "";
                                    nzero 
= nzero + 1;
                                }

                                
else
                                
{
                                    ch1 
= "";
                                    ch2 
= str2.Substring(i, 1);
                                    nzero 
= nzero + 1;
                                }

                            }

                        }

                    }

                }

                
if (i == (j - 11|| i == (j - 3))
                
{
                    
//如果该位是亿位或元位,则必须写上 
                    ch2 = str2.Substring(i, 1);
                }

                str5 
= str5 + ch1 + ch2;

                
if (i == j - 1 && str3 == "0")
                
{
                    
//最后一位(分)为0时,加上“整” 
                    str5 = str5 + '';
                }

            }

            
if (num == 0)
            
{
                str5 
= "零元整";
            }

            
return str5;
        }