Python_20200927_文件相关简单操作 

 1 #!/usr/bin/env python
 2 # encoding: utf-8
 3 # 读取中文，搜索中文
 4 import os
 5 
 6 def get_lines(fileName):#获取文件行数
 7     count = 0
 8     for index, line in enumerate(open(fileName,'rb')):
 9         count += 1
10     return count
11 
12 def loadDataSet(fileName, splitChar='\t'):#查看文件中某些行内容
13     """
14     输入：文件名
15     输出：数据集
16     描述：从文件读入数据集
17     """
18     dataSet = []
19     with open(fileName,'rb') as fr:
20         for line in fr.readlines()[0:2]:#要显示的行数
21             dataSet.append(line)
22     return dataSet
23 
24 def search_records(fileName,txt, splitChar='\t'):#遍历文件夹下文件中的内容
25     dataSet = []
26     suc=1
27     with open(fileName, 'r',encoding='utf8') as fr:
28     #with open(fileName, 'rb') as fr:二进制格式读取 ，txt需要以二进制格式搜索，前面加b
29         for line in fr.readlines():  # 要显示的行数
30             if txt in line:
31                 return suc,txt,line
32 
33 def get_nums_of_folder(path):#获取文件夹下有多少文件夹（文件）
34     # 统计 E:/ 下的文件夹个数
35     #path = "E:"
36     count = 0
37     for fn in os.listdir(path):  # fn 表示的是文件名
38         count = count + 1
39     return count
40 
41 def get_nums_of_files(path):#获取文件夹下文件数
42     # 统计 E:/201903 下的文件个数
43     # path = os.getcwd()    #获取当前路径
44     #path = "E:/201903"
45     count = 0
46     for root, dirs, files in os.walk(path):  # 遍历统计
47         for each in files:
48             count += 1  # 统计文件夹下文件个数
49     return count  # 输出结果
50 
51 if __name__ == '__main__':
52     print("start:")
53     txt='SUPAY|3100016019220056|1342933****|#011/0MuFqJm7H81vyfw5v/30Q==' #查找内容
54     #print(loadDataSet('E:/SQL.txt'))
55     #print(get_lines('E:/201903/crm_usr_info_0.txt'))
56     #print(get_lines('E:/1.txt'))
57     #print(search_records('E:/1.txt'))
58     #print(loadDataSet('E:/201903/crm_usr_info_10.txt'))
59     count=get_nums_of_files('E:/201903')
60     for i in range(0,count):
61         print('E:/201903/crm_usr_info_%s.txt' % str(i))
62         suc=search_records('E:/201903/crm_usr_info_%s.txt' % str(i),txt)
63         print(suc)
64         if isinstance(suc,tuple) and suc[0]==1:
65             print(suc[1])
66             print(suc[2])
67             break
68     print("end:")

 

posted @ 2020-09-27 10:23  hehenihaoa  阅读(105)  评论(0)    收藏  举报