实验6

实验任务4

#include <stdio.h>
#define N 10

typedef struct {
    char isbn[20]; 
    char name[80];
    char author[80];
    double sales_price;
    int sales_count;
} Book;

void output(Book x[], int n);
void sort(Book x[], int n);
double sales_amount(Book x[], int n);

int main() {
    Book x[N] = { {"978-7-5327-6082-4", "门将之死", "罗纳德.伦", 42, 51},
                 {"978-7-308-17047-5", "自由与爱之地：入以色列记", "云也退", 49 , 30},
                 {"978-7-5404-9344-8", "伦敦人", "克莱格泰勒", 68, 27},
                 {"978-7-5447-5246-6", "软件体的生命周期", "特德姜", 35, 90},
                 {"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49},
                 {"978-7-5133-5750-0", "主机战争", "布莱克.J.哈里斯", 128, 42},
                 {"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44},
                 {"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42},
                 {"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55},
                  {"978-7-229-14156-1", "源泉", "安.兰德", 84, 59} };

    printf("图书销量排名(按销售册数): \n");
    sort(x, N);
    output(x, N);

    printf("\n图书销售总额: %.2f\n", sales_amount(x, N));

    return 0;
}

void output(Book x[], int n) {
    int i;

    printf("%-25s %-25s %-25s %-25s %-25s\n", "ISBN号", "书名", "作者", "售价", "销售册数");

    for (i = 0; i < n; i++) {
        printf("%-25s %-25s %-25s %-25g %-25d\n", x[i].isbn, x[i].name, x[i].author, x[i].sales_price, x[i].sales_count);
    }
}

void sort(Book x[], int n) {
    Book t[N];
    int i, j;

    for (i = 0; i < n-1; i++) {
        for (j = i+1; j < n; j++) {
            if (x[i].sales_count < x[j].sales_count) {
                t[i] = x[i];
                x[i] = x[j];
                x[j] = t[i];
            }
        }
    }
}

double sales_amount(Book x[], int n) {
    double sum = 0.0;
    int i;

    for (i = 0; i < n; i++) {
        sum += x[i].sales_price * x[i].sales_count;
    }

    return sum;
}

 

实验任务5

#include <stdio.h>

typedef struct {
    int year;
    int month;
    int day;
} Date;

void input(Date* pd);
int day_of_year(Date d);
int compare_dates(Date d1, Date d2); 

void test1() {
    Date d;
    int i;
    
    printf("输入日期:(以形如2025-12-19这样的形式输入)\n");
    
    for (i = 0; i < 3; ++i) {
        input(&d);
        printf("%d-%02d-%02d是这一年中第%d天\n\n", d.year, d.month, d.day,
            day_of_year(d));
    }
}
void test2() {
    Date Alice_birth, Bob_birth;
    int i;
    int ans;
    printf("输入Alice和Bob出生日期:(以形如2025-12-19这样的形式输入)\n");
    for (i = 0; i < 3; ++i) {
        input(&Alice_birth);
        input(&Bob_birth);
        ans = compare_dates(Alice_birth, Bob_birth);

        if (ans == 0)
            printf("Alice和Bob一样大\n\n");
        else if (ans == -1)
            printf("Alice比Bob大\n\n");
        else
            printf("Alice比Bob小\n\n");
    }
}
int main() {
    printf("测试1: 输入日期, 打印输出这是一年中第多少天\n");
    test1();

    printf("\n测试2: 两个人年龄大小关系\n");
    test2();
}

void input(Date* pd) {
    scanf_s("%d-%2d-%2d", &pd->year,&pd->month,&pd->day);
}

int day_of_year(Date d) {
    int days[] = { 31,28,31,30,31,30,31,31,30,31,30,31 };
    int i, total = 0;

    if ((d.year % 4 == 0 && d.year % 100 != 0) || d.year % 400 == 0)
        days[1] = 29;

    for (i = 0; i < d.month - 1; i++)
        total += days[i];
    total += d.day;

    return total;
}

int compare_dates(Date d1, Date d2) {
    if (d1.year < d2.year)
        return -1;
    else if (d1.year > d2.year)
        return 1;
    else {
        if (d1.month < d2.month)
            return -1;
        else if (d1.month > d2.month)
            return 1;
        else {
            if (d1.day < d2.day)
                return -1;
            else if (d1.day > d2.day)
                return 1;
            else
                return 0;
        }
    }
}

 

实验任务6

#define  _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <string.h>

enum Role { admin, student, teacher };

typedef struct {
    char username[20]; 
    char password[20];
    enum Role type;
} Account;

void output(Account x[], int n); 

int main() {
    Account x[] = { {"A1001", "123456", student},
                    {"A1002", "123abcdef", student},
                    {"A1009", "xyz12121", student},
                    {"X1009", "9213071x", admin},
                    {"C11553", "129dfg32k", teacher},
                    {"X3005", "921kfmg917", student} };
    int n;

    n = sizeof(x) / sizeof(Account);
    output(x, n);

    return 0;
}

void output(Account x[], int n) {
    int len,i, j;
    char s[100][20];

    for (i = 0; i < n; i++) {
        len = strlen(x[i].password);
        for (j = 0; j < len; j++) {
            x[i].password[j] = '*';
        }
        x[i].password[j] = '\0';
    }

    for (i = 0; i < n; i++) {
        switch (x[i].type) {
        case 0:strcpy(s[i], "admin"); break;
        case 1:strcpy(s[i], "student"); break;
        case 2:strcpy(s[i], "teacher"); break;
        }
    }

    for (i = 0; i < n; i++) {
        printf("%-30s %-30s %-30s\n", x[i].username, x[i].password, s[i]);
    }
}

 

实验任务7

#include <stdio.h>
#include <string.h>

typedef struct {
    char name[20];
    char phone[12];
    int vip;
} Contact;

void set_vip_contact(Contact x[], int n, char name[]);
void output(Contact x[], int n);
void display(Contact x[], int n);

#define N 10
int main() {
    Contact list[N] = { {"刘一", "15510846604", 0},
                       {"陈二", "18038747351", 0},
                       {"张三", "18853253914", 0},
                       {"李四", "13230584477", 0},
                       {"王五", "15547571923", 0},
                       {"赵六", "18856659351", 0},
                       {"周七", "17705843215", 0},
                       {"孙八", "15552933732", 0},
                       {"吴九", "18077702405", 0},
                       {"郑十", "18820725036", 0} };
    int vip_cnt, i;
    char name[20];

    printf("显示原始通讯录信息: \n");
    output(list, N);

    printf("\n输入要设置的紧急联系人个数: ");
    scanf_s("%d", &vip_cnt);
    printf("输入%d个紧急联系人姓名:\n", vip_cnt);
    for (i = 0; i < vip_cnt; ++i) {
        scanf_s("%s", name);
        set_vip_contact(list, N, name);
    }

    printf("\n显示通讯录列表:(按姓名字典序升序排列,紧急联系人最先显示)\n");
    display(list, N);

    return 0;
}

void set_vip_contact(Contact x[], int n, char name[]) {
    int i;

    for (i = 0; i < n; i++) {
        if (strcmp(x[i].name, name) == 0)
            x[i].vip = 1;
    }
}

void display(Contact x[], int n) {
    int i, j, num=0;
    Contact t;

    for (i = 0; i < n; i++) {
        if (x[i].vip) {
            t = x[num];
            x[num] = x[i];
            x[i] = t;
            num++;
        }
    }

    for (i = 0; i < num-1; i++) {
        if (strcmp(x[i].name, x[i + 1].name) > 0) {
            t = x[i];
            x[i] = x[i + 1];
            x[i + 1] = t;
        }
    }

    for (i = num; i < n; i++) {
        for (j = i + 1; j < n; j++) {
            if (strcmp(x[i].name, x[j].name) > 0) {
                t = x[i];
                x[i] = x[j];
                x[j] = t;
            }
        }
    }

    output(x, n);
}
void output(Contact x[], int n) {
    int i;
    for (i = 0; i < n; ++i) {
        printf("%-10s%-15s", x[i].name, x[i].phone);
        if (x[i].vip)
            printf("%5s", "*");
        printf("\n");
    }
}