JAVA第六周作业
1.定义长度为5的整型数组,输入它们的值,用冒泡排序输出
import java.util.Scanner; public class Test02 { public static void main(String[] args) { // TODO Auto-generated method stub int[] num = new int[5]; Scanner input = new Scanner(System.in); for (int i = 0; i < num.length; i++) { System.out.print("请输入第" + (i + 1) + "个数:"); num[i] = input.nextInt(); } for (int i = 0; i < num.length - 1; i++) { for (int j = 0; j < num.length - 1 - i; j++) { if (num[j] > num[j + 1]) { int temp = num[j]; num[j] = num[j + 1]; num[j + 1] = temp; } } } for (int i = 0; i < num.length; i++) { System.out.print(num[i] + " "); } } }
2.定义数组{34,22,35,67,45,66,12,33},输入一个数a,查找在数组中是否存在,如果存在输出下标,不存在输出"not found"
package one; import java.util.Scanner; public class Test02 { public static void main(String[] args) { // TODO Auto-generated method stub int[] a = { 34, 22, 35, 67, 45, 66, 12, 33 }; Scanner input = new Scanner(System.in); System.out.println("请输入一个数:"); int b = input.nextInt(); int xiabiao = -1; for (int i = 0; i < a.length; i++) { if (a[i] == b) { xiabiao = i; System.out.println(i); break; } } if (xiabiao == -1) System.out.println("not found"); } }
3.以矩阵的形式输出一个double型二维数组(长度分别为5、4,值自己设定)的值
package one; public class Test02 { public static void main(String[] args) { // TODO Auto-generated method stub double[][] a = { { 1, 2, 3, 4 }, { 5, 6, 7, 8 }, { 9, 10, 11, 12 }, { 13, 14, 15, 16 }, { 17, 18, 19, 20 } }; for (int i = 0; i < 5; i++) { for (int j = 0; j < 4; j++) { System.out.print(a[i][j] + " "); } System.out.println(); } } }
4.定义一个二维数组(长度分别为3,4,值自己设定),求该二维数组的最大值
package one; public class Test02 { public static void main(String[] args) { // TODO Auto-generated method stub int[][] a = { { 10, 20, 30, 40 }, { 80, 70, 60, 50 }, { 90, 100, 110, 120 } }; int max = 0; for (int i = 0; i < 3; i++) { for (int j = 0; j < 4; j++) { if (a[i][j] > max) { max = a[i][j]; } } } System.out.println(max); } }
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