正则匹配

import re
import requests

url = 'http:afdfadfas'
req = requests.get(url)
num = re.findall("<p>Num is:(\d*?)</p>", req.text)
list1 = []
for i in num:
    list1.append(chr(int(i)))
    # print(chr(int(i)), end='')
str1 = ''.join(list1)
# a = '2knwympcObgehuljzforai8siuvjmbfhwrlqncOtaog5ayhelOjfxniqpzdovwtgscrb6jkupsxhzylqtegwmovOcdrif2csijlpbanrvwfxqOmedhtu5ezyjqircklagbOhvomstxdun6hapxozkbnswifguyOtcm0cyiauljxfgpbmhkOznqrsowed'
for j in str1:
    if j.isnumeric():
        print(j, end='')