剑指offer python版 合并两个排序的链表

class ListNode(object):
    def __init__(self,x):
        self.val=x
        self.next=None
        
class Link(object):
    def __init__(self,values=None):
        self.nodes=self.set_link(values) if  values else None
        
    def get_link(self):
        return self.nodes
    def set_link(self,values):
        if not values :
            return False
        head=ListNode(0)
        move=head
        
        
        try:
            for i in values:
                tmp=ListNode(i)
                move.next=tmp
                move=move.next
                
        except Exception as e:
            print(e)
            
        return head.next
def aa(head1,head2):
    if not head1:
        return head2
    if not head2:
        return head1
    if head1.val<=head2.val:
        ret=head1
        ret.next=aa(head1.next,head2)
    if head1.val>head2.val:
        ret=head2
        ret.next=aa(head1,head2.next)
        
    return ret
    

a=Link([1,2,3,3,4,5,6,7])

b=a.get_link()

c=Link([5,6,7,8,9,10])

d=c.get_link()

q=aa(b,d)

while q:
    print(q.val)
    q=q.next