1 #include<cstdio>
2 #include<cstring>
3 #include<iostream>
4 using namespace std;
5 const long long ha=100000007;
6 long long shu[2][40000],a[10004];
7 void geng(int a1,int a2,int a3,int a4)
8 {
9     if(a2+1==a3)
10       {
11         shu[0][a1]=1;
12         shu[1][a1]=1;
13         return;
14       }
15     int mid;
16     mid=(a2+a3)/2;
17     if(a4<mid)
18       geng(a1<<1,a2,mid,a4);
19     else
20       geng(a1<<1|1,mid,a3,a4);
21     shu[0][a1]=((shu[0][a1<<1]*a[a3-mid])%ha+shu[0][a1<<1|1])%ha;
22     shu[1][a1]=(shu[1][a1<<1]+(shu[1][a1<<1|1]*a[mid-a2])%ha)%ha;
23     return;
24 }
25 long long zhao(int a1,int a2,int a3,int a4,int a5,int a6)
26 {
27     if(a2==a4&&a3==a5)
28       return shu[a6][a1];
29     int mid;
30     mid=(a2+a3)/2;
31     long long le=0,re=0,sum;
32     if(a4<mid)
33       le=zhao(a1*2,a2,mid,a4,min(mid,a5),a6);
34     if(a5>mid)
35       re=zhao(a1*2+1,mid,a3,max(a4,mid),a5,a6);
36     if(a6)
37       sum=(le+(re*a[max(0,mid-a4)])%ha)%ha;
38     else
39       sum=((le*a[max(0,a5-mid)])%ha+re)%ha;
40     return sum;
41 }
42 int main()
43 {
44     int t;
45     scanf("%d",&t);
46     a[0]=1;
47     for(int i=1;i<=10000;i++)
48       a[i]=(a[i-1]*2)%ha;
49     for(int j=0;j<t;j++)
50       {
51         int n,i;
52         scanf("%d",&n);
53         memset(shu,0,sizeof(shu));
54         for( i=0;i<n;i++)
55           {
56             int a1;
57             long long a2,a3;
58             scanf("%d",&a1);
59             int len=min(a1-1,n-a1);
60             if(a1!=1&&a1!=n&&len)
61               {
62                 a2=zhao(1,1,n+1,a1-len,a1,0);
63                 a3=zhao(1,1,n+1,a1+1,a1+len+1,1);
64                 if(a2!=a3)
65                 {
66                 printf("Y\n");
67                 break;
68                 }
69               }
70             geng(1,1,n+1,a1);
71           }
72         if(i==n)
73           printf("N\n");
74         for(++i;i<n;++i)
75           scanf("%*d");
76       }
77     return 0;
78 }

posted on 2016-03-18 23:06  xiyuedong  阅读(186)  评论(0编辑  收藏  举报