有一个点超时,确实是个很简单的splay
#include<cstdio> #include<iostream> using namespace std; int n,shu[1000006][2],root,size,b1,b2,sum1,sum[1000005],zhi[1000005]; int fa[1000005]; void xuan(int a1) { int a2,a3,l,r; a2=fa[a1]; a3=fa[a2]; if(a2==root) root=a1; else if(a2==shu[a3][0]) shu[a3][0]=a1; else shu[a3][1]=a1; if(shu[a2][0]==a1) l=0; else l=1; r=l^1; fa[a1]=a3; fa[a2]=a1; shu[a2][l]=shu[a1][r]; shu[a1][r]=a2; fa[shu[a2][l]]=a2; return; } void zhuan(int a1) { int a2,a3; for(;a1!=root;) { a2=fa[a1]; a3=fa[a2]; if(a2!=root) if(a2==shu[a3][0]^a1==shu[a2][0]) xuan(a1); else xuan(a2); xuan(a1); } } void jia(int &a1,int a2,int a3) { if(a1==0) { size++; a1=size; zhi[a1]=a2; sum[a1]=1; fa[a1]=a3; zhuan(a1); return; } if(zhi[a1]==a2) sum[a1]++; else if(zhi[a1]<a2) jia(shu[a1][1],a2,a1); else jia(shu[a1][0],a2,a1); return; } void qian(int a1,int a2) { if(a1==0) return; if(zhi[a1]==a2) b1=a2; else if(zhi[a1]<a2) { b1=zhi[a1]; qian(shu[a1][1],a2); } else qian(shu[a1][0],a2); return; } void hou(int a1,int a2) { if(a1==0) return; if(zhi[a1]==a2) b2=a2; else if(zhi[a1]>a2) { b2=zhi[a1]; hou(shu[a1][0],a2); } else hou(shu[a1][1],a2); return; } int main() { scanf("%d",&n); scanf("%d",&sum1); jia(root,sum1,0); for(int i=1;i<n;i++) { int a1; scanf("%d",&a1); b1=-1; b2=-1; qian(root,a1); hou(root,a1); if(b1==-1) sum1+=b2-a1; else if(b2==-1) sum1+=a1-b1; else if(a1-b1<=b2-a1) sum1+=a1-b1; else sum1+=b2-a1; jia(root,a1,0); } printf("%d",sum1); return 0; }
posted on 2016-01-18 10:55  xiyuedong  阅读(132)  评论(0编辑  收藏  举报