344. 反转字符串

编写一个函数,其作用是将输入的字符串反转过来。输入字符串以字符数组 char[] 的形式给出。

不要给另外的数组分配额外的空间,你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。

你可以假设数组中的所有字符都是 ASCII 码表中的可打印字符。

 

示例 1:

输入:["h","e","l","l","o"]
输出:["o","l","l","e","h"]
示例 2:

输入:["H","a","n","n","a","h"]
输出:["h","a","n","n","a","H"]

来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/reverse-string

class Solution:
    def reverseString(self, s: List[str]) -> None:
        """
        Do not return anything, modify s in-place instead.
        """
        s.reverse()

 

class Solution:
    def reverseString(self, s: List[str]) -> None:
        """
        Do not return anything, modify s in-place instead.
        """
        for i in range(len(s)//2):
            s[i],s[len(s)-i-1]=s[len(s)-i-1],s[i]

 

posted @ 2020-10-08 16:21  XXXSANS  阅读(79)  评论(0编辑  收藏  举报