92. 递归实现指数型枚举

题解:递归,加数组
点击查看代码
#include<iostream>
#include<algorithm>
#include<cstring>
using namespace std;
const int N=1e5+7;
int n;
int a[N];
void dfs(int x,int idx)
{
for(int i=1;i<=idx;i++)
cout<<a[i]<<" ";
cout<<"\n";
for(int i=x;i<=n;i++)
{
a[idx+1]=i;
dfs(i+1,idx+1);
}
return ;
}
int main()
{
cin>>n;
dfs(1,0);
return 0;
}