求Π

from random import random
from math import sqrt
from time import perf_counter
DARTS = 10000000000
hits = 0.0
perf_counter()
for i in range(1, DARTS+1):
x, y = random(), random()
dist = sqrt(x ** 2 + y ** 2)
if dist <= 1.0:
hits = hits + 1
pi = 4 * (hits/DARTS)
print("Pi的值是{}.".format(pi))
print("运行时间是:{:.5f}s".format(perf_counter()))
 
 
 
posted @ 2023-11-20 23:53  夏松鼠  阅读(35)  评论(0)    收藏  举报