NEU操作系统实验课4——线程同步
实验要求：
创建两个线程按数字顺序打印10以下自然数，其中一个线程打印1-3及8-10；另一个线程打印4-6。要求使用线程同步机制实现上述打印顺序。
看网上的资料学习了两种写法
C++11的，使用了std::thread
1 #include <unistd.h> 2 #include <thread> 3 #include <iostream> 4 #include <mutex> 5 #include<bits/stdc++.h> 6 void Fun_1(); 7 void Fun_2(); 8 unsigned int counter=0; 9 std::mutex mtx; 10 11 int main() 12 { 13 std::thread thrd_1(Fun_1); 14 std::thread thrd_2(Fun_2); 15 thrd_1.join(); 16 thrd_2.join(); 17 //system("pause"); 18 return 0; 19 } 20 21 void Fun_1() 22 { 23 while(counter<10){ 24 if(counter<3||counter>5)continue; 25 std::lock_guard<std::mutex> mtx_locker(mtx); 26 ++counter; 27 std::cout << "Function 1 counting " << counter << "...\n"; 28 usleep(1); 29 } 30 } 31 32 void Fun_2() 33 { 34 while(counter<10){ 35 if(counter>2&&counter<6)continue; 36 std::lock_guard<std::mutex> mtx_locker(mtx); 37 ++counter; 38 std::cout << "Function 2 counting " << counter << "...\n"; 39 usleep(1); 40 } 41 }
C语言的，使用pthread
1 #include <stdio.h> 2 #include <pthread.h> 3 #include <stdlib.h> 4 #include <unistd.h> 5 6 pthread_mutex_t mutex; 7 pthread_cond_t cond1; 8 pthread_cond_t cond2; 9 int cnt=0; 10 11 12 void hander(void *arg) 13 { 14 free(arg); 15 (void)pthread_mutex_unlock(&mutex); 16 } 17 18 void *thread1(void *arg) 19 { 20 pthread_cleanup_push(hander,&mutex); 21 printf("thread1\n1\n2\n3\n"); 22 pthread_mutex_lock(&mutex); 23 pthread_cond_wait(&cond1,&mutex); 24 pthread_mutex_unlock(&mutex); 25 printf("thread1\n7\n8\n9\n10\n"); 26 pthread_cleanup_pop(0); 27 } 28 29 void *thread2(void *arg) 30 { 31 pthread_mutex_lock(&mutex); 32 pthread_cond_wait(&cond2,&mutex); 33 printf("thread2\n4\n5\n6\n"); 34 pthread_cond_signal(&cond1); 35 pthread_mutex_unlock(&mutex); 36 } 37 38 int main() 39 { 40 pthread_t tid1,tid2; 41 pthread_mutex_init(&mutex,NULL); 42 pthread_cond_init(&cond1,NULL); 43 pthread_cond_init(&cond2,NULL); 44 pthread_create(&tid1,NULL,thread1,NULL); 45 pthread_create(&tid2,NULL,thread2,NULL); 46 47 sleep(1); 48 pthread_cond_signal(&cond2); 49 //sleep(2); 50 pthread_exit(0); 51 return 0; 52 }
