C/C++ 结构体 指针 函数传递

#include <stdio.h>
#include <stdlib.h>

struct student{
    int num;
    char str[20];
    double dec;
};

void scan(struct student *stu[], int *n){    
    scanf("%d", n);
    *stu = (struct student *)malloc(*n * sizeof(struct student));

    for(int i = 0; i < *n; ++i){
        scanf("%d%s%lf", &(*stu)[i].num, (*stu)[i].str, &(*stu)[i].dec);
    }
}

void print(struct student stu[], int n){    

    printf("%d\n", n);
    for(int i = 0; i < n; ++i){
        printf("%d %s %lf\n", stu[i].num, stu[i].str, stu[i].dec);
    }
}

int main(){
    int n;
    struct student *stu;
    
    scan(&stu, &n);
    print(stu, n);

    free(stu);
    return 0;
}
/*
3
20 字符串0 20.02
21 字符串1 21.12
22 字符串2 22.22
*/