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Kotlin-三目表达式Kotlin版

由于Kotlin没有三目表达式这种写法,一般用if else就可以,但是写起来比较麻烦,于是我便写了个扩展函数,支持Boolean和表达式,感觉还行。如果大家有更好的方案,可以留言。

/**
 *
 * @author xunevermore
 * create on 2021/10/26 18:20
 * description:
 *
 */
fun <T> Boolean?.judge(positiveValue: T, negativeValue: T) =
    if (this != null && this) positiveValue else negativeValue

fun <T> Boolean?.judge(positiveValueProvider: () -> T, negativeValueProvider: () -> T): T =
    if (this != null && this) positiveValueProvider() else negativeValueProvider()


private const val TAG = "BooleanJudgeExt"

fun test() {
    var value: Nothing? = null
    val a = value.judge(1, 2)
    Log.i(TAG, "test:$a ")

    val b = value.judge({ true }, { false })
    Log.i(TAG, "test: $b")

    val x = 0
    val c = (x == 1).judge( "x is 1" ,  "x is not 1" )
    Log.i(TAG, "test: $c")

}
posted @ 2022-03-26 12:45  徐影魔  阅读(132)  评论(0)    收藏  举报