摘要:
//回溯算法 #include#include#include using namespace std;int a[101];int n=4; int sum=0,flag=0;void digui(int k){ if(k==n+1) { sum++; return; } for(int ... 阅读全文
posted @ 2017-03-09 20:38
X_na
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摘要:
N皇后问题 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 21808 Accepted Submission(s): 974... 阅读全文
posted @ 2017-03-09 19:37
X_na
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