hdu 1012 u Calculate e

u Calculate e

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 44729    Accepted Submission(s): 20522


Problem Description
A simple mathematical formula for e is



where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.
 

Output
Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.
 

Sample Output
n e - ----------- 0 1 1 2 2 2.5 3 2.666666667 4 2.708333333
 

Source
#include<iostream>
#include<math.h>
#include<string>
#include<algorithm>
using namespace std;
int jc(int n)
{
	int k=1;
	for(int i=1;i<=n;i++)
	  	k=k*i;
	return k;
}
int main()
{ 
    cout<<"n e"<<endl;
    cout<<"- -----------"<<endl;
    cout<<"0 1"<<endl;
    double sum=1;
    for(int i=1;i<=9;i++)
    {   
        sum+=1.0/jc(i);
        if(i>2)
        	printf("%d %.9lf\n",i,sum);
        else
    	cout<<i<<" "<<sum<<endl;
	}
    
}


 

posted @ 2017-03-04 17:52  X_na  阅读(134)  评论(0)    收藏  举报