每日日报

今日练习

四则运算JAVA半成品版

此代码将之前的C++版改为了JAVA版,并又添置了些功能。

代码如下:

package homework;
import java.util.*;
import java.util.Scanner;
import javax.script.*;
public class math
{
private static int n,min,max,c,cc,kh=0,xz;
private static char[] d={'+','-','*','/'};
private static Scanner sc=new Scanner(System.in);
public static void main(String args[])
{
DZ();
TM();
}
public static void DZ()//菜单
{
System.out.println( "请输入题目总数:" );
n=sc.nextInt();
System.out.println("请选择:");
System.out.println(" 1.小学二年级口算题");
System.out.println(" 2.小学三年级口算题");
System.out.println(" 3.小学四年级口算题");
xz=sc.nextInt();
System.out.println("请输入数值的范围.");
min=sc.nextInt();
max=sc.nextInt();
switch(xz)
{
case 1:
while(max>100)
{
System.out.println("小学二年级操作数范围不超过100,请重新输入最大值:");
max=sc.nextInt();
}
c=1;
break;
case 2:
while(max>1000)
{
System.out.println("小学三年级操作数范围不超过1000,请重新输入最大值:");
max=sc.nextInt();
}
System.out.println( "输入操作数个数:" );
c=sc.nextInt()-1;
while(c>3)
{
System.out.println("小学三年级操作数不超过4个,请重新输入操作数个数:");
c=sc.nextInt()-1;
}
break;
case 3:
System.out.println( "输入操作数个数:" );
c=sc.nextInt()-1;
while(c>4)
{
System.out.println("小学四年级操作数不超过5个,请重新输入操作数个数:");
c=sc.nextInt()-1;
}
System.out.println( "是否有括号?是请输入1,否请输入0:" );
kh=sc.nextInt();
break;
}
System.out.println( "是否有乘除法?是请输入1,否请输入0:" );
cc=sc.nextInt();
}
public static String Tm()//每题
{
Random r=new Random();
int sz;
String ch=null;
double a=r.nextInt(max)+min;
while(a>max){a=r.nextInt(max)+min;}
if(xz==1)
{
int b;
if(cc==0) {sz=r.nextInt(2);}
else{sz=r.nextInt(4);}//乘除法
b=r.nextInt(max)+min;
while(b>max){b=r.nextInt(max)+min;}
if(d[sz]=='/')
{
if(b==0){while(b==0||b>max) {b=r.nextInt(max)+min;}}//防止0为被除数
if(a%b!=0)
{
while(a%b!=0||a>max||b>max)
{
a=r.nextInt(max)+min;
b=r.nextInt(max)+min;
}
}
}
ch=String.valueOf(a);
ch+=String.valueOf(d[sz]);
ch+=String.valueOf(b);
}
else
{
double[] b=new double[c];//操作数个数及数值范围
int k=-1,h=-1,z;
if(kh==1)//括号
{
z=r.nextInt(2);
if(z==1)//随机增加括号
{
k=r.nextInt(c-1);
if(k==0)//括号由开头起
{
ch=String.valueOf('(');
ch+=String.valueOf(a);
h=r.nextInt(c-1)+k+1;
while(h>c){h=r.nextInt(c-1)+k+1;}
}
if(k>0)//括号在式中
{
ch=String.valueOf(a);
h=r.nextInt(c)+k+1;
while(h>c){h=r.nextInt(c)+k+1;}
}
}
else{ch=String.valueOf(a);}
}
else{ch=String.valueOf(a);}
for(int i=0;i<c;i++)
{
if(cc==0) {sz=r.nextInt(2);}
else {sz=r.nextInt(4);}//乘除法
ch+=String.valueOf(d[sz]);
if(k>0&&i==k-1){ch+=String.valueOf('(');}
b[i]=r.nextInt(max)+min;
while(b[i]>max){b[i]=r.nextInt(max)+min;}
if(d[sz]=='/'&&b[i]==0){while(b[i]==0||b[i]>max) {b[i]=r.nextInt(max)+min;}}//防止0为被除数
ch+=String.valueOf(b[i]);
if(i==h-1){ch+=String.valueOf(')');}//补“)”
}
}
return ch;//以字符串形式定义算式
}
public static void TM()//总题
{
int j=0;
String[] s=new String[n];
while(j<n)//制作题目
{
s[j]=Tm();
if(PC(j,s)==0)//重复
{
System.out.println((j+1)+"、"+s[j]+"=");
j++;
}
}
ScriptEngine se=new ScriptEngineManager().getEngineByName("JavaScript");
double[] sum=new double[n];
for(int i=0;i<n;i++)
{
try{sum[i]=(Double)se.eval(s[i]);}
catch(ScriptException e){e.printStackTrace();}
}//字符串转算式计算结果
DT(s,sum);//答题
}
public static int PC(int j,String[] s)//判重
{
for(int i=0;i<j;i++){if(s[i].equals(s[j])) {return 1;}}
return 0;
}
public static void DT(String[] s,double[] sum)//答题
{
int min,yd=0,w=0,yn;
double[] da=new double[n];//回答
double[] Da=new double[n];
double[] Sum=new double[n];
String[] Cw=new String[n];//错误题号
System.out.println( "请设置答题时间(分钟)");
min=sc.nextInt();
System.out.println( "开始答题 !");
long startTime=System.currentTimeMillis();
while((System.currentTimeMillis()-startTime)/1000<=min*60)
{
da[yd]=sc.nextDouble();
yd++;
if(yd==n){break;}
}
if(yd!=n){System.out.println( "时间到!答题结束!");}
for(int i=0;i<n;i++)
{
if(da[i]!=sum[i])//判断答题对错
{
Cw[w]=s[i];
Da[w]=da[i];
Sum[w]=sum[i];
w++;
}
}
double cw=(double)(n-w)*100/n;//正确率
System.out.println( "你的正确率为 :" +cw+"%");
System.out.println( "你的错题如下 :");//错题
for(int i=0;i<w;i++){System.out.println((i+1)+"、"+Cw[i]+"="+Da[i]+" X"+" 正确答案:"+Sum[i]);}
while(true)
{
System.out.println( "你想重练错题吗?是请输入1,否请输入0:");
yn=sc.nextInt();
if(yn==0){break;}
for(int i=0;i<w;i++)
{
System.out.println((i+1)+"、"+Cw[i]+"=");
da[i]=sc.nextDouble();
if(da[i]!=Sum[i]){System.out.println( "X 正确答案为:"+Sum[i]);}
}
}
}
}

posted @ 2020-10-26 13:26  禁小呆  阅读(64)  评论(0)    收藏  举报