细究,有点意思的极坐标题
已知\(\left\{ \begin{array}{ll} \rho =\dfrac{4}{1-2\cos\theta} \\ \theta=\dfrac{5\pi}{6} \end{array} \right.\),则\(\rho=\underline{\qquad\blacktriangle\qquad}.\)
数形结合!!!
每周看看我,冲进985!【魏刚的作品,转载须声明】
已知\(\left\{ \begin{array}{ll} \rho =\dfrac{4}{1-2\cos\theta} \\ \theta=\dfrac{5\pi}{6} \end{array} \right.\),则\(\rho=\underline{\qquad\blacktriangle\qquad}.\)