实验四
实验任务一
1.1
#include<stdio.h> #define N 4 int main(){ int a[N] = {2,0,2,3}; char b[N] = {'2','0','2','3'}; int i; printf("sizeof(int) = %d\n",sizeof(int)); printf("sizeof(char) = %d\n",sizeof(char)); printf("\n"); for (i = 0;i < N;++i) printf("%p:%d\n",&a[i],a[i]); printf("\n"); for (i = 0;i < N;++i) printf("%p:%c\n",&b[i],b[i]); printf("\n"); printf("a = %p\n",a); printf("b = %p\n",b); return 0; }

1.连续存放,每个元素占四个字节
2.连续存放,每个元素占一个字节
3.一样
1.2
#include<stdio.h> #define N 2 #define N 3 int main(){ int a[N][M] = {{1,2,3},{4,5,6}}; char b[N][M] = {{'1','2','3'},{'4','5','6'}}; int i,j; for (i = 0;i < N;++i) for (j = 0;j < N;++j) printf("%p:%d\n",&a[i][j],a[i][j]); printf("\n"); printf("a = %p\n",a); printf("a[0] = %p\n",a[0]); printf("a[1] = %p\n",a[1]); printf("\n"); for (i = 0;i < N;++i) for (j = 0;j < N;++j) printf("%p:%c\n",&b[i][j],b[i][j]); printf("\n"); printf("b = %p\n",b); printf("b[0] = %p\n",b[0]); printf("b[1] = %p\n",b[1]); printf("\n"); return 0; }

1.按行连续存放,占四个字节
2.一样的
3.按行连续存放,占一个字节
4.一样的
5.分别是a,b[0][0]和a,b[1][0]的值
实验任务二
#include<stdio.h> #include<string.h> #define N 80 void swap_str(char s1[N],char s2[N]); void test1(); void test2(); int main(){ printf("测试1:用两个一维维数组,实现两个字符串交换\n"); test1(); printf("\n测试:用二维数组,实现两个字符串交换\n"); test2(); return 0; } void test1(){ char views1[N] = "hey,C,I hate u."; char views2[N] = "hey,C,I love u."; printf("交换前:\n"); puts(views1); puts(views2); swap_str(views1,views2); printf("交换后:\n"); puts(views1); puts(views2); } void test2(){ char views[2][N] ={"hey,C,I hate u.", "hey,C,I love u."} ; printf("交换前:\n"); puts(views[0]); puts(views[1]); swap_str(views[0],views[1]); printf("交换后:\n"); puts(views[0]); puts(views[1]); } void swap_str(char s1[N],char s2[N]){ char tmp[N]; strcpy(tmp,s1); strcpy(s1,s2); strcpy(s2,tmp); }

二维数组的行在交换前已被固定,相当于一维数组
实验任务三
3.1
#include <stdio.h> #define N 80 int count(char x[]); int main() { char words[N+1]; int n; while(gets(words) != NULL) { n = count(words); printf("单词数: %d\n\n", n); } return 0; } int count(char x[]) { int i; int word_flag = 0; int number = 0; for(i = 0; x[i] != '\0'; i++) { if(x[i] == ' ') word_flag = 0; else if(word_flag == 0) { word_flag = 1; number++; } } return number; }

3.2
#include <stdio.h> #define N 1000 int main() { char line[N]; int word_len; int max_len; int end; int i; while(gets(line) != NULL) { word_len = 0; max_len = 0; end = 0; i = 0; while(1) { while(line[i] == ' ') { word_len = 0; i++; } while(line[i] != '\0' && line[i] != ' ') { word_len++; i++; } if(max_len < word_len) { max_len = word_len; end = i; } if(line[i] == '\0') break; } printf("最长单词: "); for(i = end - max_len; i < end; ++i) printf("%c", line[i]); printf("\n\n"); } return 0; }

实验任务四
#include<stdio.h> #define N 5 void input(int x[], int n); void output(int x[], int n); double average(int x[], int n); void bubble_sort(int x[], int n); int main(){ int scores[N]; double ave; printf("录入%d个分数:\n", N); input(scores, N); printf("\n输出课程的分数:\n"); output(scores, N); printf("\n课程分数处理:计算均分、排序...\n"); ave=average(scores, N); bubble_sort(scores, N); printf("\n输出课程均分:%.2f\n",ave); printf("\n输出课程分数(高-->低):\n"); output(scores, N); return 0; } //保存 void input(int x[], int n){ int i; for(i = 0; i < n; ++i) scanf("%d", &x[i]); } //输出 void output(int x[], int n){ int i; for(i = 0; i < n; ++i) printf("%d ", x[i]); printf("\n"); } //平均 double average(int x[], int n){ int i; int sum=0; double ave; for(i = 0;i < n; i++){ sum=sum+x[i]; } ave=sum/n; return ave; } //排序 void bubble_sort(int x[], int n){ int i,t,j; for(i = 0; i < n ; i++){ for(j = i; j < n; j++) if(x[i] < x[j+1]){ t = x[i]; x[i] = x[j+1]; x[j+1] = t; } } }

实验任务五
#include <stdio.h> #define N 100 void dec2n(int x, int n); char hhh(int y); int main() { int x; printf("输入一个十进制整数: "); while(scanf("%d", &x) != EOF) { dec2n(x, 2); // 函数调用: 把x转换成二进制输出 dec2n(x, 8); // 函数调用: 把x转换成八进制输出 dec2n(x, 16); // 函数调用: 把x转换成十六进制输出 printf("\n输入一个十进制整数: "); } return 0; } void dec2n(int x, int n){ int i=0,j=0; int a[N]={0}; while(x){ a[i]=x%n; x/=n; i++; } for(j=i-1;j>=0;j--){ if(a[j]<0){ return; } else if(a[j]>=0&&a[j]<10) { printf("%d",a[j]); } else { printf("%c",hhh(a[j])); } } printf("\n"); } char hhh(int y){ int i=0; i=y-10; return 'A'+i; }

实验任务六
#include<stdio.h> #define N 100 #define M 4 void output(int x[][N],int n); void rotate_to_right(int x[][N],int n); int main() { int t[][N]={{1,2,3,4}, {5,6,7,8}, {9,10,11,12}, {13,14,15,16}}; printf("原始矩阵:\n"); output(t,M); rotate_to_right(t,M); printf("变换后矩阵:\n"); output(t,M); return 0; } void output(int x[][N],int n) { int i,j; for(i=0;i<n;++i) { for(j=0;j<n;++j) printf("%4d",x[i][j]); printf("\n"); } } void rotate_to_right(int x[][N],int n) { int i,j,y[n]; for(i=0;i<n;++i) y[i]=x[i][n-1]; for(i=0;i<n;++i) { for(j=n-1;j>=1;--j) x[i][j]=x[i][j-1]; x[i][0]=y[i]; } }

实验任务七
7.1
#include <stdio.h> #define N 80 void replace(char x[],char old_char,char new_char); int main(){ char text[N]="c programming is difficult or not,it is a question."; printf("原始文本:"); printf("%s\n",text); replace(text,'i','*'); printf("处理后文本:"); printf("%s\n",text); return 0; } void replace(char x[],char old_char,char new_char){ int i; for(i=0;x[i]!='\0';i++) if(x[i]==old_char) x[i]=new_char; }

#include <stdio.h>
#define N 80 int main() { char str[N], ch; int i; printf("输入字符串: "); gets(str); printf("输入一个字符: "); ch = getchar(); printf("截断处理......"); i = 0; while (str[i] != '\0') { if (str[i] == ch) break; i++; } str[i] = '\0'; printf("\n截断处理后字符串: %s\n", str); #include <stdio.h#include <string.
#define N 5 #define M 20 void bubble_sort(char str[][M], int n); int main() { char name[][M] = {"Bob", "Bill", "Joseph", "Taylor", "George"}; int i; printf("输出初始名单:\n"); for (i = 0; i < N; i++) printf("%s\n", name[i]); printf("\n排序中...\n"); bubble_sort(name, N); printf("\n按字典序输出名单:\n"); for (i = 0; i < N; i++) printf("%s\n", name[i]); return 0; }
void bubble_sort(char str[][M], int n) { char temp[M]; int i, j; for(i = 0; i < n - 1; i++) for(j = 0; j < n - 1 - i; j++) if(strcmp(str[j], str[j + 1]) > 0) { strcpy(temp, str[j]); strcpy(str[j], str[j + 1]); strcpy(str[j + 1], temp); } }

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