4.23 java作业

1、编写一个简单程序,要求数组长度为5,分别赋值10,20,30,40,50,在控制台输出该数组的值。(知识点:数组定义和创建、一维数组初始化)[必做题]?

 1 package XSC;
 2 
 3 public class work {
 4 
 5     /**
 6      * @param args
 7      */
 8     public static void main(String[] args) {
 9         // TODO Auto-generated method stub
10 
11          int[] a = {10, 20, 30, 40, 50};
12           for (int i = 0; i < a.length; i++) {
13             System.out.println(a[i]);
14     }
15 
16     }
17 
18 }

 

2、将一个字符数组的值(neusofteducation)拷贝到另一个字符数组中。(知识点:数组复制) [必做题]?

 1 package XSC;
 2 
 3 public class work {
 4 
 5     /**
 6      * @param args
 7      */
 8     public static void main(String[] args) {
 9         // TODO Auto-generated method stub
10 
11         char[] a = {'n', 'e', 'u', 's', 'o', 'f', 't', 'e', 'd', 'u', 'c', 'a', 't', 'i', 'o', 'n'};
12         char[] b = new char[a.length];
13         for (int i = 0; i < a.length; i++) {
14             b[i]=a[i];
15             System.out.println(b[i]);
16         }
17 
18     }
19 
20 }

3、给定一个有9个整数(1,6,2,3,9,4,5,7,8)的数组,先排序,然后输出排序后的数组的值。(知识点:Arrays.sort排序、冒泡排序)

 1 package XSC;
 2 
 3 public class work {
 4 
 5     /**
 6      * @param args
 7      */
 8     public static void main(String[] args) {
 9         // TODO Auto-generated method stub
10 
11         int a[] =new int[]{1,6,2,3,9,4,5,7,8};
12         for (int i = 0; i < a.length; i++) {
13                  for (int j = i; j < a.length; j++) {
14                      if(a[i]>a[j]){
15                         int x =a[i];
16                         a[i] =a[j];
17                        a[j] =x;
18                     }
19                 }
20             }
21              for (int i = 0; i < a.length; i++) {
22                 System.out.print(a[i]+" ");
23              }
24 
25     }
26 
27 }

4、 输出一个double型二维数组(长度分别为5、4,值自己设定)的值。(知识点:数组定义和创建、多维数组初始化、数组遍历)

public class work {

    /**
     * @param args
     */
    public static void main(String[] args) {
        // TODO Auto-generated method stub

        double a[][] =new double[5][4];
        for (int i = 0; i < 5; i++) {
           for (int j = 0; j < 4; j++) {
               a[i][j] =i+j;
           }
      }

       for (int i = 0; i < 5; i++) {
            for (int j = 0; j <4; j++) {
               System.out.print(a[i][j]+" ");
           }
           System.out.println();
        }

    }

}

 

 

5、 在一个有8个整数(18,25,7,36,13,2,89,63)的数组中找出其中最大的数及其下标。(知识点:数组遍历、数组元素访问) [必做题]?

 1 package XSC;
 2 
 3 public class work {
 4 
 5     /**
 6      * @param args
 7      */
 8     public static void main(String[] args) {
 9         // TODO Auto-generated method stub
10 
11         int a[]={18,25,7,36,13,2,89,63};
12         int max=a[0];
13         int maxidx=0;
14      for (int i = 1; i < a.length; i++) {
15           if (a[i]>max) {
16              max=a[i];
17              maxidx=i;
18          }    
19      }
20       System.out.println("最大值数是"+max+"它的下标是"+maxidx);
21 
22     }
23 
24 }

 

 

6、将一个数组中的元素逆序存放(知识点:数组遍历、数组元素访问)

 1 package XSC;
 2 import java.util.Scanner;
 3 public class work {
 4 
 5     /**
 6      * @param args
 7      */
 8     public static void main(String[] args) {
 9         // TODO Auto-generated method stub
10         Scanner input=new Scanner(System.in);
11         int a[]=new int[5];
12         for (int i = a.length; i >0; i--) {
13             a[i-1]=input.nextInt();
14         }
15         System.out.println("倒序输出");
16        for (int i = 0; i < a.length; i++) {
17             System.out.print(a[i]+" ");
18         }
19     }
20 
21 }

 

 

7. 将一个数组中的重复元素保留一个其他的清零。(知识点:数组遍历、数组元素访问)

 1 package XSC;
 2 import java.util.Scanner;
 3 public class work {
 4 
 5     /**
 6      * @param args
 7      */
 8     public static void main(String[] args) {
 9         // TODO Auto-generated method stub
10         Scanner input=new Scanner(System.in);
11         int a[]=new int[10];
12            for (int i = 0; i < a.length; i++) {
13                a[i]=input.nextInt();
14           }
15           for (int i = 0; i < a.length-1; i++) {
16               for (int j = i+1; j < a.length; j++) {
17                    if(a[i]==a[j]){
18                       a[j]=0;
19                   }
20               }
21           }
22           System.out.println("新数组为");
23          for (int i = 0; i < a.length; i++) {
24               System.out.print(a[i]+" ");
25            }
26     }
27 
28 }

 

 

8、给定一维数组{ -10,2,3,246,-100,0,5},计算出数组中的平均值、最大值、最小值。(知识点:数组遍历、数组元素访问)

 1 package XSC;
 2 public class work {
 3 
 4     /**
 5      * @param args
 6      */
 7     public static void main(String[] args) {
 8         // TODO Auto-generated method stub
 9          int a[]={-10,2,3,246,-100,0,5};
10          double max=0,min=0,sum=0,avg=0;
11           max=a[0];
12           min=a[0];
13           for (int i = 0; i < a.length; i++) {
14               sum+=a[i];
15              if (max<a[i]) {
16                    max=a[i];
17               }
18               if (min>a[i]) {
19                   min=a[i];
20               }
21           }
22           avg=sum/7.0;
23          System.out.println("最大值为"+max);
24          System.out.println("最小值为"+min);
25            System.out.println("平均值为"+avg);
26     }
27 
28 }

 

 

9、使用数组存放裴波那契数列的前20项 ,并输出 1 1 2 3 5 8 13 21

 1 package XSC;
 2 public class work {
 3 
 4     /**
 5      * @param args
 6      */
 7     public static void main(String[] args) {
 8         // TODO Auto-generated method stub
 9         int a[]=new int[20];
10         a[0]=1;a[1]=1;
11         for(int i=2;i<a.length;i++){
12             a[i]=a[i-1]+a[i-2];
13         }
14        for (int i = 0; i < a.length; i++) {
15       System.out.println(a[i]+" ");
16    }
17 
18     
19     }
20 }

 

 

10、生成一个长度为10的随机整数数组(每个数都是0-100之间),输出,排序后,再输出

 1 package XSC;
 2 
 3 import java.util.Random;
 4 
 5 public class work {
 6 
 7     /**
 8      * @param args
 9      */
10     public static void main(String[] args) {
11         // TODO Auto-generated method stub
12         Random r=new Random();
13         int a[]=new int[10];
14         for (int i = 0; i < a.length; i++) {
15             a[i]=r.nextInt(100);
16             System.out.println(a[i]);
17         }
18        int temp=0;
19         for (int i = 0; i < a.length-1; i++) {
20             for (int j = 0; j < a.length-1-i; j++) {
21                 if (a[j]<a[j+1]) {
22                    temp=a[j];
23                     a[j]=a[j+1];
24                     a[j+1]=temp;
25                }
26             }
27     
28         }
29         System.out.println("排序后");
30         for (int i = 0; i < a.length; i++) {
31             System.out.print(a[i]+" ");
32        }
33 
34     
35     }
36 }

 

posted @ 2021-05-12 15:46  辛事成  阅读(56)  评论(0编辑  收藏  举报