摘要:
题目关键是建模,之后就是简单地增广路。#include#include#include#include#includeusing namespace std;const int N=1024;const int inf=1q;void ford(){ int a[N],vis[... 阅读全文
摘要:
#include#include#includeusing namespace std;const int N=200000+5;const int inf=1<<24;int dp[N][2],a[N];char s[2*N];int main(){ int n,m,i,_;... 阅读全文