摘要:
#pragma comment(linker, "/STACK:102400000,102400000")#include#include#include#includeusing namespace std;const int N=1024;const int inf=1edges... 阅读全文
posted @ 2015-08-13 19:20
xryz
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#include #include #include #include #include #include using namespace std;int gcd(int u,int v){ if(u10*180) difms=10*360-difms; if(d... 阅读全文
posted @ 2015-08-13 17:13
xryz
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摘要:
题目关键是建模,之后就是简单地增广路。#include#include#include#include#includeusing namespace std;const int N=1024;const int inf=1q;void ford(){ int a[N],vis[... 阅读全文
posted @ 2015-08-13 10:52
xryz
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