POJ 2502 - Subway Dijkstra堆优化试水

做这道题的动机就是想练习一下堆的应用,顺便补一下好久没看的图论算法。

Dijkstra算法概述

//从0出发的单源最短路

dis[][] = {INF}
ReadMap(dis);
for i = 0 -> n - 1
    d[i] = dis[0][i]
while u = GetNearest(1 .. n - 1, !been[])
    been[u] = 1
    for_each edge from u
        d[edge.v] = min(d[edge.v], d[u] + dis[u][edge.v])

上述算法遍历所有节点,每次 GetNearest() 循环一次,并遍历了所有边,算法复杂度 O(V2+E) = O(V2)

其中 GetNearest() 总取未去过的点中 d[] 最小的点,可以用小根堆维护 d[] 数组优化。

堆优化算法概述

//从0出发的单源最短路

dis[][] = {INF}
ReadMap(dis);
for i = 0 -> n - 1
    d[i] = dis[0][i]
heap = BuildHeap(d[], n - 1)
while u = heap.pop()
    been[u] = 1
    for_each edge from u
        if IsBetterDist()
            d[edge.v] = d[u] + dis[u][edge.v]
            heap.up(heap.IndexOf(edge.v))

建堆 O(VlogV),n次pop() O(VlogV),遍历边并更新堆 O(ElogV),优化算法复杂度 O(2VlogV+ElogV) = O((V+E)logV)

其他心得

* 几何类最短路一定要判重点

//POJ 2502
//Dijkstra 堆优化试水
//飘忽不定的迷离的数据
//AC 2016-10-17

#define HEAP_OPTIMIZE

#include <cstdio>
#include <cstring>
#include <iostream>
#include <cstdlib>
#include <cmath>
#include <algorithm>
#define MAXN (200 + 2) + 10
#define SUB_SPEED (40000.0 / 60.0)
#define WALK_SPEED (10000.0 / 60.0)
#define INF 0x7f7f7f7f
using namespace std;

inline double sqr(int x){
    return x * x;
}

struct point {
    int x, y;
    point(){}
    point(int X, int Y): x(X), y(Y){}
    inline double norm(){
        return sqrt(sqr(x) + sqr(y));
    }
    friend point operator - (const point &p1, const point &p2){
        return point(p1.x - p2.x, p1.y - p2.y);
    }
    friend bool operator == (const point &p1, const point &p2){
        return (p1.x == p2.x) && (p1.y == p2.y);
    }
}pt[MAXN];

int n = 0;

int IndexOf(const point &p){
    for (int i = 0; i < n; i++){
        if (pt[i] == p)
            return i;
    }
    return n;
}

double dis[MAXN][MAXN], d[MAXN];
bool been[MAXN];

struct BHeap{
    int heap[MAXN], n, index[MAXN];
    BHeap(): n(0){}
    BHeap(int N): n(0){
        for (int i = 1; i <= N; i++)
            push(i);
    }
    void down(int i){
        for (int j = 2 * i; j <= n; j <<= 1){
            j += j < n && d[heap[j]] > d[heap[j + 1]];
            if (d[heap[j]] < d[heap[i]]){
                swap(index[heap[i]], index[heap[j]]);
                swap(heap[i], heap[j]);
                i = j;
            }
            else break;
        }
    }
    void up(int i){
        for (int j = i/2; j > 0; j >>= 1){
            if (d[heap[j]] > d[heap[i]]){
                swap(index[heap[i]], index[heap[j]]);
                swap(heap[i], heap[j]);
                i = j;
            }
            else break;
        }
    }
    void push(int a){
        heap[++n] = a;
        index[a] = n;
        up(n);
    }
    int pop(){
        if (!n) return 0;
        swap(index[heap[1]], index[heap[n]]);
        swap(heap[1], heap[n--]);
        down(1);
        return heap[n + 1];
    }
}heap;

int main(){
    freopen("fin.c", "r", stdin);
    for (int i = 0; i < MAXN; i++)
        for(int j = 0; j < MAXN; j++)
			if (i == j) dis[i][j]=0;
			else dis[i][j] = INF;
    scanf("%d%d%d%d", &pt[0].x, &pt[0].y, &(pt[1].x), &pt[1].y);
    n = 2;
    dis[0][1] = dis[1][0] = (pt[0] - pt[1]).norm() / WALK_SPEED;
    point p;
    while (~scanf("%d%d", &p.x, &p.y)){
        int iter = IndexOf(p), olditer = - 1;
        if (iter == n){
            pt[n++] = p;
            for (int i = 0; i < n; i++){
                dis[i][n - 1] = dis[n - 1][i] = (pt[n - 1] - pt[i]).norm() / WALK_SPEED;
            }
        }
        olditer = iter;
        while (scanf("%d%d", &p.x, &p.y), ~p.x && ~p.y){
            int iter = IndexOf(p);
            if (iter == n){
                pt[n++] = p;
                for (int i = 0; i < n; i++){
                    if (i != olditer)
                        dis[i][n - 1] = dis[n - 1][i] = (pt[n - 1] - pt[i]).norm() / WALK_SPEED;
                    else
                        dis[i][n - 1] = dis[n - 1][i] = (pt[n - 1] - pt[i]).norm() / SUB_SPEED;
                }
            }
            else dis[olditer][iter] = dis[iter][olditer] = (pt[iter] - pt[olditer]).norm() / SUB_SPEED;
            olditer = iter;
        }
    }
    for (int i = 1; i < n; i++)
        d[i] = dis[0][i];
    #ifdef HEAP_OPTIMIZE
        heap = BHeap(n - 1);
    #endif
    while (
    #ifdef HEAP_OPTIMIZE
        int v = heap.pop()
    #else
        1
    #endif
    ){
        #ifndef HEAP_OPTIMIZE
	        double minn = INF;
	        int v = - 1;
	        for (int i = 1; i < n; i ++)
	            if ((!been[i])&&(d[i] < minn)){
	                minn = d[i];
	                v = i;
	            }
	        if (!~v) break;
        #endif
        been[v] = 1;
        for (int i = 1; i < n; i++){
            if (!been[i]){
                if (d[v] + dis[v][i] < d[i]){
                    d[i] = d[v] + dis[v][i];
                    #ifdef HEAP_OPTIMIZE
                        heap.up(heap.index[i]);
                    #endif
                }
            }
        }
    }
    printf("%.f\n", d[1]);
}

 

posted on 2016-10-17 21:02  xlnx  阅读(233)  评论(0)    收藏  举报

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