37、将相同字段属性值放在同一个数组中,并去重对象数组

            const data = [{
                    featureName: "age",
                    bucket: "0-10",
                    iv: 100
                },
                {
                    featureName: "gender",
                    bucket: "男",
                    iv: 200
                },
                {
                    featureName: "city",
                    bucket: "安徽",
                    iv: 300
                }, {
                    featureName: "age",
                    bucket: "20-30",
                    iv: 110
                }, {
                    featureName: "city",
                    bucket: "北京",
                    iv: 310
                }
            ];
            // 将相同字段featureName的值放到同一数组中
            function mergeObject(data) {
                var arrayFilted = [];
                data.forEach(function(value, key) {
                    if(arrayFilted.length == 0) {
                        arrayFilted.push({
                            featureName: value.featureName,
                            bucket: [value.bucket],
                            iv: [value.iv]
                        });
                    } else {
                        arrayFilted.forEach(function(item, index) {
                            if(item.featureName && item.featureName !== value.featureName) {
                                arrayFilted.push({
                                    featureName: value.featureName,
                                    bucket: [value.bucket],
                                    iv: [value.iv]
                                });
                            } else if(item.featureName && item.featureName === value.featureName) {
                                item.bucket.push(value.bucket)
                                item.iv.push(value.iv)
                            }
                        });
                    }
                });
                return arrayFilted;
            }

            //去重
            function Es5duplicate(arr, type) {
                var newArr = [];
                var tArr = [];
                if(arr.length == 0) {
                    return arr;
                } else {
                    if(type) {
                        for(var i = 0; i < arr.length; i++) {
                            if(!tArr[arr[i][type]]) {
                                newArr.push(arr[i]);
                                tArr[arr[i][type]] = true;
                            }
                        }
                        return newArr;
                    } else {
                        for(var i = 0; i < arr.length; i++) {
                            if(!tArr[arr[i]]) {
                                newArr.push(arr[i]);
                                tArr[arr[i]] = true;
                            }
                        }
                        return newArr;
                    }
                }
            }

            const getData = mergeObject(data);
            console.log(Es5duplicate(getData, 'featureName'));

最终结果:

posted @ 2019-09-03 18:05  要什么自行车y  阅读(732)  评论(0编辑  收藏  举报