python 共用两个列表的循环

lena=len(agents)
    tt0=tt1=tt2=tt3=tt4=tt5=tt6=tt7=tt8=tt9=tt10=tt11=tt12=tt13=0
    tta0=tta1=tta2=tta3=tta4=tta5=tta6=tta7=tta8=tta9=tta10=tta11=tta12=tta13=0
    ttv=1200
    ttva=0
    result=[]
    for agent,cookie,namea in zip(agents,Cookies,name):
        querySign(cookie, namea,agent)
    for  ii in range(13):
        attva=0
        ata=0
        for agent,cookie,namea in zip(agents,Cookies,name):
            ata=ata+1
            if ata in result:
                continue
            ayy=openBoxa(cookie,namea,agent)
            print(ata,result,ayy)
            if ayy==-1:
                result.append(ata)
            if ttva<ayy:
                ttva=ayy
        if len(result)==lena:
            break
        print(ttva+5)
        time.sleep(ttva)