【Python】BeautifulSoup的使用

  1、遍历文档树

  使用示例:

html_doc = """
<html><head><title>The Dormouse's story</title></head>
    <body>
<p class="title"><b>The Dormouse's story</b></p>

<p class="story">Once upon a time there were three little sisters; and their names were
<a href="http://example.com/elsie" class="sister" id="link1">Elsie</a>,
<a href="http://example.com/lacie" class="sister" id="link2">Lacie</a> and
<a href="http://example.com/tillie" class="sister" id="link3">Tillie</a>;
and they lived at the bottom of a well.</p>

<p class="story">...</p>
"""

from bs4 import BeautifulSoup
soup = BeautifulSoup(html_doc, 'html.parser')

  1.1、子节点

  一个Tag可能包含多个字符串或其它的Tag,这些都是这个Tag的子节点.Beautiful Soup提供了许多操作和遍历子节点的属性.

  注意: Beautiful Soup中字符串节点不支持这些属性,因为字符串没有子节点

  1.2、tag的名字

  操作文档树最简单的方法就是告诉它你想获取的tag的name.如果想获取 <head> 标签,只要用 soup.head :

soup.head
# <head><title>The Dormouse's story</title></head>

soup.title
# <title>The Dormouse's story</title>

  这是个获取tag的小窍门,可以在文档树的tag中多次调用这个方法.下面的代码可以获取<body>标签中的第一个<b>标签:

soup.body.b
# <b>The Dormouse's story</b>

  通过点取属性的方式只能获得当前名字的第一个tag:

soup.a
# <a class="sister" href="http://example.com/elsie" id="link1">Elsie</a>

  如果想要得到所有的<a>标签,或是通过名字得到比一个tag更多的内容的时候,就需要用到 Searching the tree 中描述的方法,比如: find_all()

soup.find_all('a')
# [<a class="sister" href="http://example.com/elsie" id="link1">Elsie</a>,
#  <a class="sister" href="http://example.com/lacie" id="link2">Lacie</a>,
#  <a class="sister" href="http://example.com/tillie" id="link3">Tillie</a>]

  1.3、.contents和.children

  tag的 .contents 属性可以将tag的子节点以列表的方式输出:

head_tag = soup.head
head_tag
# <head><title>The Dormouse's story</title></head>

head_tag.contents
[<title>The Dormouse's story</title>]

title_tag = head_tag.contents[0]
title_tag
# <title>The Dormouse's story</title>
title_tag.contents
# [u'The Dormouse's story']

  BeautifulSoup 对象本身一定会包含子节点,也就是说<html>标签也是 BeautifulSoup 对象的子节点:

len(soup.contents)
# 1
soup.contents[0].name
# u'html'

  字符串没有 .contents 属性,因为字符串没有子节点:

text = title_tag.contents[0]
text.contents
# AttributeError: 'NavigableString' object has no attribute 'contents'

  通过tag的 .children 生成器,可以对tag的子节点进行循环: 

for child in title_tag.children:
    print(child)
    # The Dormouse's story

  1.4、.descendants

  .contents 和 .children 属性仅包含tag的直接子节点.例如,<head>标签只有一个直接子节点<title>

  但是<title>标签也包含一个子节点:字符串 “The Dormouse’s story”,这种情况下字符串 “The Dormouse’s story”也属于<head>标签的子孙节点. .descendants 属性可以对所有tag的子孙节点进行递归循环 [5] :

for child in head_tag.descendants:
    print(child)
    # <title>The Dormouse's story</title>
    # The Dormouse's story

  1.5、.string

  如果tag只有一个 NavigableString 类型子节点,那么这个tag可以使用 .string 得到子节点:

title_tag.string
# u'The Dormouse's story'

  1.6、.strings和stripped_strings

  如果tag中包含多个字符串 [2] ,可以使用 .strings 来循环获取:

for string in soup.strings:
    print(repr(string))
    # u"The Dormouse's story"
    # u'\n\n'
    # u"The Dormouse's story"
    # u'\n\n'
    # u'Once upon a time there were three little sisters; and their names were\n'
    # u'Elsie'
    # u',\n'
    # u'Lacie'
    # u' and\n'
    # u'Tillie'
    # u';\nand they lived at the bottom of a well.'
    # u'\n\n'
    # u'...'
    # u'\n'

 2、父节点

  2.1、.parent

  通过 .parent 属性来获取某个元素的父节点.在例子“爱丽丝”的文档中,<head>标签是<title>标签的父节点:

title_tag = soup.title
title_tag
# <title>The Dormouse's story</title>
title_tag.parent
# <head><title>The Dormouse's story</title></head>

  2.2、.parents

  通过元素的 .parents 属性可以递归得到元素的所有父辈节点,下面的例子使用了 .parents 方法遍历了<a>标签到根节点的所有节点.

link = soup.a
link
# <a class="sister" href="http://example.com/elsie" id="link1">Elsie</a>
for parent in link.parents:
    if parent is None:
        print(parent)
    else:
        print(parent.name)
# p
# body
# html
# [document]
# None

 3、兄弟节点

  3.1、.next_sibling和.previous_sibling

  在文档树中,使用 .next_sibling 和 .previous_sibling 属性来查询兄弟节点:

sibling_soup.b.next_sibling
# <c>text2</c>

sibling_soup.c.previous_sibling
# <b>text1</b>

  3.2、.next_siblings和.previous_siblings

  通过 .next_siblings 和 .previous_siblings 属性可以对当前节点的兄弟节点迭代输出:

for sibling in soup.a.next_siblings:
    print(repr(sibling))
    # u',\n'
    # <a class="sister" href="http://example.com/lacie" id="link2">Lacie</a>
    # u' and\n'
    # <a class="sister" href="http://example.com/tillie" id="link3">Tillie</a>
    # u'; and they lived at the bottom of a well.'
    # None

for sibling in soup.find(id="link3").previous_siblings:
    print(repr(sibling))
    # ' and\n'
    # <a class="sister" href="http://example.com/lacie" id="link2">Lacie</a>
    # u',\n'
    # <a class="sister" href="http://example.com/elsie" id="link1">Elsie</a>
    # u'Once upon a time there were three little sisters; and their names were\n'
    # None

 

posted @ 2020-03-11 14:53  Mr·Xu  阅读(258)  评论(0编辑  收藏  举报