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SQL行列转换实战

Posted on 2006-02-10 15:03  晰雨的天空  阅读(1550)  评论(1)    收藏  举报

 行列转换实例
                  表ttt有三个字段
                  seq  --序列
                  jcxm --检查项目
                  zhi  --值

                  数据分别如下:
                  seq   jcxm       zhi
                  -------      --------          --------
                  11     1    0.50
                  11     2    0.21
                  11     3    0.25
                  12     1    0.24
                  12     2    0.30
                  12     3    0.22                            

                  实现功能
                  创建视图时移动行值为列值


                  create view v_view1
                  as
                  select seq,
                         sum(decode(jcxm,1, zhi)) 检测项目1,
                         sum(decode(jcxm,2, zhi)) 检测项目2,
                         sum(decode(jcxm,3, zhi)) 检测项目3
                  from ttt
                  group by seq;

                  序号 检测项目1  检测项目2  检测项目3
                  11     0.50    0.21     0.25
                  12     0.24    0.30     0.22

 

                  技巧:
                  用THEN中的0和1来进行统计(SUM)

                  jcxm   zhi
                  ----   ----
                  a           1
                  b           1
                  a           3
                  d           2
                  e           4
                  f           5
                  a           5
                  d           3
                  d           6
                  b           5
                  c           4
                  b           3
                  求他的zhi既是1,也是3,也是5的jcxm
                  方法一
                  select jcxm
                  from ttt
                  group by jcxm
                  having sum(decode(zhi,1,-1,3,-1,5,-1,0)) = -3
                  方法二
                  select jcxm from ttt
                  group by jcxm having (sign(sum(decode(zhi,1,-1,0)))+
                  sign(sum(decode(zhi,3,-1,0)))+sign(sum(decode(zhi,5,-1,0)))<=-3);

                  ----------
                  a
                  b
                  说明:
                  sign()函数根据某个值是0、正数还是负数,分别返回0、1、-1
                  所以可以用sign和decode来完成比较字段大小来区某个字段
                  select decode(sign(字段1-字段2),-1,字段3,字段4) from dual;

                  sign是一个对于写分析SQL有很强大的功能
                  下面我对sign进行一些总结:
                  但属性student取0和1以外的值,或者student取两个以上的标法值,问题就不会这么简单了
                  解决办法就是特征函数(abs(),sign())

                  常用的特征算法
                  [A=B]=1-abs(sign(A-B))
                  [A!=B]=abs(sign(A-B))
                  [A<B]=1-sign(1+sign(A-B))
                  不能用-sign(A-B):因为如果不满足A<b则返回-1,而不是0,这样就不能用在字段选择上了
                  [A<=B]=sign(1-sign(A-B))
                  [A>B]=1-sign(1-sign(A-B))
                  [A>=B]=sign(1+sign(A-B)))
                  [NOTα]=1-d [α]
                  [αANDb ]=d [α]*d [b ] (6)
                  [αOR b ]=sign(d [α]+d [b ])

                  例如:
                  A<B                         Decode( Sign(A-B), -1, 1, 0 )     
                    
                  A<=B                         Decode( Sign(A-B), 1, 0, 1 )     
                    
                  A>B                         Decode( Sign(A-B), 1, 1, 0 )      
                   
                  A>=B                         Decode( Sign(A-B), -1, 0, 1 )    
                     
                  A=B                         Decode( A, B, 1, 0 )        
                  A between B and C      Decode( Sign(A-B), -1, 0,
                  Decode(Sign(A-C), 1, 0, 1 ))        
                  A is null                       Decode(A,null,1,0)        
                  A is not null                 Decode(A,null,0,1)         A in
                  (B1,B2,...,Bn)  Decode(A,B1,1,B2,1,...,Bn,1,0)        
                  nor LogA                    Decode( LogA, 0, 1, 0 )           
                    (1-Sign(LogA))
                  LogA and LogB            LogA * LogB
                  LogA or LogB              LogA + LogB
                  LogA xor LogB            Decode(Sign(LogA),Sign(LogB),0,1)   
                  Mod(Sign(LogA),Sign(LogB),2


                  >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>

                  [NextPage]
                  另外一个关于成绩的分析例子

                  SELECT
                  SUM(CASE WHEN cj <60 THEN 1 ELSE 0 END) as "not passed",
                  SUM(CASE WHEN cj BETWEEN 60 AND 79 THEN 1 ELSE 0 END) as
                  "passed",
                  SUM(CASE WHEN cj BETWEEN 80 AND 89 THEN 1 ELSE 0 END) as
                  "good",
                  SUM(CASE WHEN cj >=90 THEN 1 ELSE 0 END) as "Excellent"
                  FROM cjtable;

                  decode用法2
                  表、视图结构转化
                  现有一个商品销售表sale,表结构为:
                  month    char(6)      --月份
                  sell    number(10,2)    --月销售金额

                  现有数据为:
                  200001  1000
                  200002  1100
                  200003  1200
                  200004  1300
                  200005  1400
                  200006  1500
                  200007  1600
                  200101  1100
                  200202  1200
                  200301  1300

                  想要转化为以下结构的数据:
                  year   char(4)          --年份
                  ------------   ---------------------        
                  -------------------
                  month1  number(10,2)   --1月销售金额
                  month2  number(10,2)   --2月销售金额
                  month3  number(10,2)   --3月销售金额
                  month4  number(10,2)   --4月销售金额
                  month5  number(10,2)   --5月销售金额
                  month6  number(10,2)   --6月销售金额
                  month7  number(10,2)   --7月销售金额
                  month8  number(10,2)   --8月销售金额
                  month9  number(10,2)   --9月销售金额
                  month10  number(10,2)     --10月销售金额
                  month11  number(10,2)     --11月销售金额
                  month12  number(10,2)     --12月销售金额

                  结构转化的SQL语句为:
                  create or replace view
                  v_sale(year,month1,month2,month3,month4,month5,month6,month7,month8,month9,month10,month11,month12)
                  as
                      select
                      substrb(month,1,4),
                      sum(decode(substrb(month,5,2),'01',sell,0)),
                      sum(decode(substrb(month,5,2),'02',sell,0)),
                      sum(decode(substrb(month,5,2),'03',sell,0)),
                      sum(decode(substrb(month,5,2),'04',sell,0)),
                      sum(decode(substrb(month,5,2),'05',sell,0)),
                      sum(decode(substrb(month,5,2),'06',sell,0)),
                      sum(decode(substrb(month,5,2),'07',sell,0)),
                      sum(decode(substrb(month,5,2),'08',sell,0)),
                      sum(decode(substrb(month,5,2),'09',sell,0)),
                      sum(decode(substrb(month,5,2),'10',sell,0)),
                      sum(decode(substrb(month,5,2),'11',sell,0)),
                      sum(decode(substrb(month,5,2),'12',sell,0))
                      from sale
                      group by substrb(month,1,4);

                  体会:要用decode /group by/ order by/sign/sum来实现不同报表的生成
                  >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
                  CASE应用

                  1        1        部门a        800        男
                  2        2        部门b        900        女
                  3        3        部门a        400        男
                  4        4        部门d        1400        女
                  5        5        部门e        1200        男
                  6        6        部门f        500        男
                  7        7        部门a        300        女
                  8        8        部门d        1000        男
                  9        9        部门d        1230        女
                  10        10        部门b        2000        女
                  11        11        部门c        2000        男
                  12        12        部门b        1200        男

                    SELECT jcxm as 部门,COUNT(seq) as 人数,
                      SUM(CASE SEX WHEN 1 THEN 1 ELSE 0 END) as 男,
                            SUM(CASE SEX WHEN 2 THEN 1 ELSE 0 END) as 女,
                      SUM(CASE SIGN(zhi-800) WHEN -1 THEN 1 ELSE 0 END) as
                  小于800元,
                      SUM((CASE SIGN(zhi-800)*SIGN(zhi-1000)                   
                  /*用*来实现<和>功能*/
                           WHEN -1 THEN 1 ELSE 0 END)+(CASE zhi
                           WHEN 800  THEN 1 ELSE 0 END)) as 从800至999,        
                  /*注意别名不能以数字开头*/
                      SUM((CASE SIGN(zhi-1000)*SIGN(zhi-1200)
                           WHEN -1 THEN 1 ELSE 0 END)+(CASE zhi
                           WHEN 1000 THEN 1 ELSE 0 END)) as 从1000元至1199元,
                      SUM((CASE SIGN(zhi-1200) WHEN 1 THEN 1 ELSE 0 END)
                      +(CASE zhi WHEN 1200 THEN 1 ELSE 0 END)) as 大于1200元
                  FroM ttt
                  GROUP BY jcxm

                  部门名 人数    男       女   小于800元 从800至999 从1000元至1199元   大于1200元
                  部门a        3        2        1        2        1           0  
                                             0
                  部门b        3        1        2        0        1           0  
                                             2
                  部门c        1        1        0        0        0           0  
                                            1
                  部门d        3        1        2        0        0           1  
                                            2
                  部门e        1        1        0        0        0             0
                                              1
                  部门f        1        1        0        1        0           0  
                                            0