【python刷题】二维数组的旋转

matrix = [[1,2,3,4],[5,6,7,8],[9,10,11,12]]

顺序旋转

def order_rotate(matrix):
    res = list(zip(*matrix))
    res = [alist[::-1] for alist in res]
    return res
res1 = order_rotate(matrix)
print(res1)

[(9, 5, 1), (10, 6, 2), (11, 7, 3), (12, 8, 4)]

逆序旋转

def reverse_rotate(matrix):
    res = list(zip(*matrix))[::-1]
    return res
res2 = reverse_rotate(matrix)
print(res2)

[(4, 8, 12), (3, 7, 11), (2, 6, 10), (1, 5, 9)]

应用：顺序打印数组

def print_matrix(matrix):
    res = []
    while len(matrix) > 0:
        res.extend(matrix[0])
        matrix = list(zip(*matrix[1:]))[::-1]
    return res

res = print_matrix(matrix)
print(res)

[1, 2, 3, 4, 8, 12, 11, 10, 9, 5, 6, 7]