Python第一周_所写代码_作业

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在目录下创建一个locked_user的文档用于被函数读取

# Author:转载
import os

current_path = os.getcwd()  # 获取当面目录
db_username = ['alex', 'xiaoya', 'kunpeng', 'asd']  # 用户名数据库，用户名不能是一样的
db_password = [123, 123, 123, 123]  # 密码可以是一样的

locked_file = open(current_path + '/locked_user.txt')  # 打开文件
locked_info = locked_file.readlines()  # 获取被锁定用户的信息。readlines一次读取所有文件，并返回list.因为我们不止锁定一个用户，所以用这个方法
locked_file.close()

count = 3
while count > 0:
    count -= 1
    username = input('username:').lower()
    if (username + '\n') in locked_info:  # 判断用户是否被锁定，加\n是因为下面用了追加模式，每追加一个用户名就重起一行
        print('用户名已被锁定')
        break
    password = int(input('password:'))
    if username in db_username and password in db_password:  # 用户名和密码都在数据库里才能验证通过
        print('welcome')
        break
    else:
        if username in db_username:
            if count == 0:
                locked_file = open(current_path + '/locked_user.txt', 'a')  # 在locked_user.txt里用追加模式储存这个用户名，每追加一个重起一行
                locked_file.write(username + '\n')
                locked_file.close()
                print('登录三次失败，用户名被锁定')
            else:
                print('用户名或错误，你还有{}次机会'.format(count))
        else:
            if count == 0:
                print('用户名不存在，登陆失败')
            else:
                print('用户名不存在,你还有{}次机会'.format(count))

附上流程图：(这个是我写的，不保证能走得通)
　　　　

 

 

 

文字游戏

# Author:转载

date = {
    '北京':{
            "平昌":{
                "沙河":{"腾讯","华为","小米"},
                "天同怨":{"百度","链家地产","我爱我家地产"}
            },
            "朝阳":{
                "望京":{"奔驰","宝马","福特","长安"},
                "国贸":{"CICC","ATCC","HP"},
                "东直门":{"华硕","阿里巴巴","京东"}
            }
    },
    '四川':{
            "成都":{
                "青羊":{"八宝街","春熙路","阳公桥"},
                "武侯":{"武侯祠","外双楠","火车北站"},
                "双流":{"蛟龙港","海滨城","双流万达广场"},
                "郫县":{"红光镇","富士康","联想"}
            },
            "绵阳":{
                "万顺":{"草上飞"},
                "城区":{"ODDL","DBCC"}
            },
            "西昌":{
                "南城":{"长途汽车站","东方元"},
                "北城":{"琼海","火车站","工业区"}
            }
    },
    '云南':{
            "昆明":{
                "城南":{"大学城","双都飞"},
                "城北":{"工业区","农业区"}
            },
            "西双版纳":{
                "南城":{"旅游区","度假区","休闲区"},
                "西城":{"娱乐区","双阳区","不知道"}
            },
            "昭通":{
                "南城":{"山顶","无极"},
                "东城":{"火车站","汽车站"}
            }
    },
    '广东':{
            "珠海":{
                "北城":{"商业","旅游","工作"},
                "西城":{"富家","双极"}
            },
            "东莞":{
                "城西":{"吃","喝","玩","OPP"}
            },
            "佛山":{
                "北城":{"美的","OPPO","VIVO","HUAWEI"},
                "东城":{"格力","长虹","小天使"}
            }
    }
}
exit_flag = False
# while循环 可以多次返回
while True :
    # for循环遍历字典中的数据
    for i in  date :
        print(i)
    # 用户输入选择进入
    choice = input("选择进入>>>>>")
    if choice in date :
        while not exit_flag :
    #输入选择后 用for循环再次遍历字典的下一层 再次让用户选择输入 再进入下一层 一次循环进入下一层
            for two in date[choice] :
                print("\t",two)
            choice2 = input("选择进入2>>>>>")
            if choice2 in date[choice] :
                while not exit_flag :
                    for therr in  date[choice][choice2]:
                        print("\t\t",therr)
                    # 进入字典的第三层
                    choice3 = input("选择进入3>>>>")
                    if choice3 in date[choice][choice2]:
                            for frou in date[choice][choice2][choice3]:
                                print("\t\t",frou)
                            # 这里是最后一层  让用户选择输入 输入B 就返回上一级
                            choice4 = input("这里是最后一层,输入B/b返回")
                            # 判断用户输入的是什么
                            if choice4 == "B" or choice4 == "b":
                                pass
                            # 如果输入Q就退出  下面的内容都是一样的道理
                            elif choice4 == "q" or choice4 == "Q":
                                exit_flag = True

                    if choice3 == "b" or choice3 == "B":
                        break
                    elif choice3 == "q" or choice3 == "Q":
                        exit_flag = True
            if choice2 ==  "b" or choice2 == "B":
                break
            elif choice2 == "q" or choice2 == "Q":
                exit_flag = True

附上我的流程图: