190. Reverse Bits 反转二进制
Reverse bits of a given 32 bits unsigned integer.
For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000).
Follow up:
If this function is called many times, how would you optimize it?
Related problem: Reverse Integer
Credits:
Special thanks to @ts for adding this problem and creating all test cases.
求一个数二进制反转
将一个32位整型转成二进制后,反转,再转换回10进制
class Solution:# @param n, an integer# @return an integerdef reverseBits(self, n):reBin = '{0:b}'.format(n).zfill(32)[::-1]return int(reBin, 2)

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