191. 求1的位数 Number of 1 Bits
Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as the Hamming weight).
For example, the 32-bit integer ’11' has binary representation 00000000000000000000000000001011, so the function should return 3.
求一个无符号整形转换成二进制后,为1的位数
public int HammingWeight(uint n) {int sum = 0;while (n > 0){if ((n&1) == 1){sum++;}n >>= 1;}return sum;}

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