LeetCode之“树”:Sum Root to Leaf Numbers
题目要求:
Given a binary tree containing digits from 0-9 only, each root-to-leaf path could represent a number.
An example is the root-to-leaf path 1->2->3 which represents the number 123.
Find the total sum of all root-to-leaf numbers.
For example,
1 / \ 2 3
The root-to-leaf path 1->2 represents the number 12.
The root-to-leaf path 1->3 represents the number 13.
Return the sum = 12 + 13 = 25.
这道题利用深度优先搜索即可,具体程序(4ms)如下:
1 /** 2 * Definition for a binary tree node. 3 * struct TreeNode { 4 * int val; 5 * TreeNode *left; 6 * TreeNode *right; 7 * TreeNode(int x) : val(x), left(NULL), right(NULL) {} 8 * }; 9 */ 10 class Solution { 11 public: 12 int sumNumbers(TreeNode* root) { 13 int totalSum = 0; 14 sumNumbersSub(root, 0, totalSum); 15 return totalSum; 16 } 17 18 void sumNumbersSub(TreeNode *tree, int sum, int &totalSum) 19 { 20 if(!tree) 21 return; 22 23 sum = sum * 10 + tree->val; 24 if(!tree->left && !tree->right) 25 { 26 totalSum += sum; 27 return; 28 } 29 30 sumNumbersSub(tree->left, sum, totalSum); 31 sumNumbersSub(tree->right, sum, totalSum); 32 } 33 34 };

浙公网安备 33010602011771号