随笔分类 -  数学问题

数值的整数次方
摘要：给定一个double类型的浮点数base和int类型的整数exponent。求base的exponent次方。 1 class Solution { 2 public: 3 double Power(double base, int exponent) { 4 if (exp... 阅读全文
posted @ 2016-01-21 17:00 小爷 阅读(136) 评论(0) 推荐(0)
斐波那契数列
摘要：题目描述大家都知道斐波那契数列，现在要求输入一个整数n，请你输出斐波那契数列的第n项。 1 class Solution { 2 public: int Fibonacci(int n) { 5 if (n ==0 || n ==1) 6 return... 阅读全文
posted @ 2016-01-21 16:20 小爷 阅读(158) 评论(0) 推荐(0)
1010. Radix (25)
摘要：Given a pair of positive integers, for example, 6 and 110, can this equation 6 = 110 be true? The answer is "yes", if 6 is a decimal number and 110 is... 阅读全文
posted @ 2015-02-28 10:55 小爷 阅读(203) 评论(0) 推荐(0)
1081. Rational Sum (20)
摘要：时间限制400 ms内存限制65536 kB代码长度限制16000 B判题程序Standard作者CHEN, YueGiven N rational numbers in the form "numerator/denominator", you are supposed to calculate ... 阅读全文
posted @ 2015-02-13 16:09 小爷 阅读(245) 评论(0) 推荐(0)
1059. Prime Factors (25)
摘要：时间限制50 ms内存限制65536 kB代码长度限制16000 B判题程序Standard作者HE, QinmingGiven any positive integer N, you are supposed to find all of its prime factors, and write ... 阅读全文
posted @ 2015-02-07 23:54 小爷 阅读(255) 评论(0) 推荐(0)
1029. Median (25)
摘要：时间限制400 ms内存限制65536 kB代码长度限制16000 B判题程序Standard作者CHEN, YueGiven an increasing sequence S of N integers, themedianis the number at the middle position.... 阅读全文
posted @ 2015-02-06 09:18 小爷 阅读(270) 评论(0) 推荐(0)
数学问题
摘要：A + B分数: 1.8时间限制：1 秒内存限制：32 兆特殊判题：否提交：171解决：85标签A+B字符串与数字对应字符串处理题目描述读入两个小于100的正整数A和B,计算A+B.需要注意的是:A和B的每一位数字由对应的英文单词给出.输入格式测试输入包含若干测试用例,每个测试用例占一行,格式为"A... 阅读全文
posted @ 2015-02-06 07:38 小爷 阅读(448) 评论(0) 推荐(0)
1058 A+B in Hogwarts (20)
摘要：1 #include 2 int main() 3 { 4 int ans1[3]; 5 int ans2[3]; 6 while(scanf("%d.%d.%d %d.%d.%d",&ans1[0],&ans1[1],&ans1[2],&ans2[0],&ans2[1],&a... 阅读全文
posted @ 2015-01-31 23:45 小爷 阅读(163) 评论(0) 推荐(0)
1005 Spell It Right (20)
摘要：1 #include 2 #include 3 #include 4 using namespace std; 5 6 int main() 7 { 8 string str; 9 char num[10][6]={"zero","one","two","three","f... 阅读全文
posted @ 2015-01-31 23:37 小爷 阅读(129) 评论(0) 推荐(0)
1065. A+B and C (64bit)
摘要：1 #include 2 #include 3 int main() 4 { 5 long long a,b,c,sum; 6 int n,i; 7 while(scanf("%d",&n)!=EOF) 8 { 9 for(i=1;i0&&b>0... 阅读全文
posted @ 2015-01-31 23:32 小爷 阅读(182) 评论(0) 推荐(0)
1002. A+B for Polynomials (25)
摘要：时间限制400 ms内存限制32000 kB代码长度限制16000 B判题程序Standard作者CHEN, YueThis time, you are supposed to find A+B where A and B are two polynomials.InputEach input fi... 阅读全文
posted @ 2015-01-31 07:34 小爷 阅读(156) 评论(0) 推荐(0)
1011. World Cup Betting (20)（最大值）
摘要：With the 2010 FIFA World Cup running, football fans the world over were becoming increasingly excited as the best players from the best teams doing ba... 阅读全文
posted @ 2015-01-30 07:43 小爷 阅读(197) 评论(0) 推荐(0)
1015. Reversible Primes (20)
摘要：Areversibleprimeinanynumbersystemisaprimewhose"reverse"inthatnumbersystemisalsoaprime.Forexampleinthedecimalsystem73isareversibleprimebecauseitsrevers... 阅读全文
posted @ 2015-01-30 07:40 小爷 阅读(264) 评论(0) 推荐(0)
三种交换两个整数的方法
摘要：交换 int a， int b1、最弱的方法1 void swap(int &a,int &b)2 {3 int c = a;4 a = b;5 b = c;6 }2、不用另外开辟空间的方法1 void swap(int &a,int &b)2 {3 a=a+b;4 ... 阅读全文
posted @ 2015-01-29 08:18 小爷 阅读(292) 评论(0) 推荐(0)
计算十进制整数的二进制中的1的数目
摘要：1 #include 2 int getbit( int a,int i) 3 { 4 return a&(1 if(n&1 == 0) n/=pow(2,x) ----> n >>= x n*=pow(2,x) ----> n <<= x|或（或1为1） 阅读全文
posted @ 2015-01-29 07:42 小爷 阅读(250) 评论(0) 推荐(0)
General Palindromic Number (进制)
摘要：A number that will be the same when it is written forwards or backwards is known as a Palindromic Number. For example, 1234321 is a palindromic number... 阅读全文
posted @ 2015-01-28 13:35 小爷 阅读(240) 评论(0) 推荐(0)
Palindromic Number (还是大数)
摘要：A number that will be the same when it is written forwards or backwards is known as a Palindromic Number. For example, 1234321 is a palindromic number... 阅读全文
posted @ 2015-01-22 07:28 小爷 阅读(310) 评论(0) 推荐(0)
Have Fun with Numbers (大数)
摘要：Notice that the number 123456789 is a 9-digit number consisting exactly the numbers from 1 to 9, with no duplication. Double it we will obtain 2469135... 阅读全文
posted @ 2015-01-22 07:26 小爷 阅读(474) 评论(0) 推荐(0)