$.each遍历json对象

var json = [
    {"id":"1","tagName":"apple"},
    {"id":"2","tagName":"orange"},
    {"id":"3","tagName":"banana"},
    {"id":"4","tagName":"watermelon"},
    {"id":"5","tagName":"pineapple"}
];
 
$.each(json, function(idx, obj) {
    alert(obj.tagName);
});
上面的代码片断工作正常,提示 “apple”, “orange” … 等,如预期一样。
 
问题: JSON 字符串
下面的例子中,声明了一个JSON字符串(随附单或双引号)直接地。
var json = '[{"id":"1","tagName":"apple"},{"id":"2","tagName":"orange"},
{"id":"3","tagName":"banana"},{"id":"4","tagName":"watermelon"},
{"id":"5","tagName":"pineapple"}]';
 
$.each(json, function(idx, obj) {
    alert(obj.tagName);
});
在Chrome中,它显示在控制台下面的错误:
 
Uncaught TypeError: Cannot use 'in' operator to search for '156'
in [{"id":"1","tagName":"apple"}...
解决方案:JSON字符串转换为JavaScript对象。
要修复它,通过标准JSON.parse()或jQuery 的 $.parseJSON 将其转换为JavaScript对象。
 
var json = '[{"id":"1","tagName":"apple"},{"id":"2","tagName":"orange"},
{"id":"3","tagName":"banana"},{"id":"4","tagName":"watermelon"},
{"id":"5","tagName":"pineapple"}]';
 
$.each(JSON.parse(json), function(idx, obj) {
    alert(obj.tagName);
});
 
//or
 
$.each($.parseJSON(json), function(idx, obj) {
    alert(obj.tagName);
});

 

 
 
posted on 2018-01-04 20:58  小碎步  阅读(287)  评论(0编辑  收藏  举报