sort counter 排序 

 1    
 2 --------------------对象用Counter-------------------------------------------------------------
 3 
 4 dc={"james":4,"kim":3,"marry":5,"bill":6}
 5 from collections import Counter
 6 counts=Counter(dc)
 7 counts
 8 >>Counter({'bill': 6, 'marry': 5, 'james': 4, 'kim': 3})    
 9 counts.most_common(3)
10 >>[('bill', 6), ('marry', 5), ('james', 4)]
11 
12 
13 #-------------------数组用sorted operator ----------------------------------------------
14 dc=[{'name':"james",'v':4},{'name':"kim",'v':3},{'name':"marry",'v':5},{'name':"bill",'v':6}]
15 import operator
16 print dc
17 >>[{'name': 'bill', 'v': 6}, {'name': 'james', 'v': 4}, {'name': 'kim', 'v': 3}, {'name': 'marry', 'v': 5}]
18 print sorted(dc,key=operator.itemgetter("v"),reverse=True)
19 >>[{'name': 'bill', 'v': 6}, {'name': 'marry', 'v': 5}, {'name': 'james', 'v': 4}, {'name': 'kim', 'v': 3}]

 

 1 # ----Counter 可用于频次统计 
 2 ar=[1,2,2,3,5,6,6,5,5,6]
 3 counts=Counter(ar)
 4 print counts
 5 >>Counter({5: 3, 6: 3, 2: 2, 1: 1, 3: 1})
 6 #输出是个对象 
 7 for k in counts:
 8     print  str(k)+" "+str(counts[k])
 9 >>
10 1 1
11 2 2
12 3 1
13 5 3
14 6 3
15 
16 print counts.most_common()
17 >>[(5, 3), (6, 3), (2, 2), (1, 1), (3, 1)]

 

posted @ 2014-06-12 16:25  zhangxiaodel  阅读(3175)  评论(0)    收藏  举报