Array Partition I

Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible.

Example 1:

Input: [1,4,3,2]

Output: 4
Explanation: n is 2, and the maximum sum of pairs is 4 = min(1, 2) + min(3, 4).

 

 

对其进行排序。

class Solution {
    public int arrayPairSum(int[] nums) {
        Arrays.sort(nums);
        int sum=0;
        for(int i=0;i<nums.length;i+=2)
            sum+=nums[i];
        
        return sum;
    }
}

 

posted on 2017-12-17 12:45  夜的第八章  阅读(113)  评论(0编辑  收藏  举报

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