【js监听报错】页面监听js报错问题 

<html>
<head>
<script type="text/javascript">
    
// 页面监听js报错问题
onerror=handleErr

var txt=""
function handleErr(msg,url,l)
{
txt="本页中存在错误如下：\n\n"
txt+="错误：" + msg + "\n"
txt+="URL: " + url + "\n"
txt+="行：" + l + "\n\n"
alert(txt)
console.log(txt)
return true
}

function message()
{
addalert("Welcome guest!")
lert("Welcome guest!")
}
message()
</script>
</head>

<body>
<input type="button" value="查看消息" />
</body>

</html>

 

 

posted @ 2019-08-19 11:04  JeckHui  阅读(2242)  评论(0)    收藏  举报