LeetCode Easy: 48. Rotate Image
一、题目
You are given an n x n 2D matrix representing an image.
Rotate the image by 90 degrees (clockwise).
Note:
You have to rotate the image in-place, which means you have to modify the input 2D matrix directly. DO NOT allocate another 2D matrix and do the rotation.
Example 1:
Given input matrix = [ [1,2,3], [4,5,6], [7,8,9] ], rotate the input matrix in-place such that it becomes: [ [7,4,1], [8,5,2], [9,6,3] ]
Example 2:
Given input matrix = [ [ 5, 1, 9,11], [ 2, 4, 8,10], [13, 3, 6, 7], [15,14,12,16] ], rotate the input matrix in-place such that it becomes: [ [15,13, 2, 5], [14, 3, 4, 1], [12, 6, 8, 9], [16, 7,10,11] ]
题意:给定一个矩阵,顺时针旋转90度。
二、思路

三、代码
#coding:utf-8
import numpy as np
class Solution:
def rotate(self, matrix):
"""
:type matrix: List[List[int]]
:rtype: void Do not return anything, modify matrix in-place instead.
"""
print("old:",'\n', matrix)
n = np.shape(matrix)[0]
# 沿着副对角线反转
for i in range(n):
for j in range(n-i):
temp = matrix[i][j]
matrix[i][j] = matrix[n-1-j][n-1-i]
matrix[n-1-j][n-1-i] = temp
#沿着水平中线反转
for i in range(n//2):
for j in range(n):
temp = matrix[i][j]
matrix[i][j] = matrix[n-1-i][j]
matrix[n-1-i][j] = temp
print('new:','\n', matrix)
if __name__ == '__main__':
a = [[1,2,3],
[4,5,6],
[7,8,9]
]
ss = Solution()
ss.rotate(a)
既然无论如何时间都会过去,为什么不选择做些有意义的事情呢
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