Ajax实现判断用户名是否已被注册

1.初始化对象,建立连接,并发送消息

 1 <script type="text/javascript">
 2         function checkUser(username){//检测是否为空,不为空进行异步检测
 3             if(username.value == ""){
 4                 alert("请输入用户名!");
 5                 username.focus();
 6                 return;
 7             }
 8             else{
 9                 createRequest('checkUser.jsp?user='+username.value);
10             }
11         }
12         function createRequest(url){//初始化对象,建立连接,并发送请求
13             var xmlhttp;
14             if(window.XMLHttpRequest){
15                 //code for IE7+,Firefox,Chrome,Opera,Safari
16                 xmlhttp = new XMLHttpRequest();
17             }else{
18                 //code for IE6,IE5
19                 xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
20             }
21             if(!xmlhttp){//如果不存在
22                 alert("不能创建XMLHttpRequest对象实例");
23                 return false;
24             }            
25             xmlhttp.onreadystatechange = function(){
26                 if(xmlhttp.readyState == 4 && xmlhttp.status == 200){
27                     document.getElementById("myDiv").innerHTML=xmlhttp.responseText;
28                 }
29             }
30             xmlhttp.open("GET",url,true);
31             xmlhttp.send();
32         }
33     </script>

2.body表单:

 1 <body>
 2     <form action="" method="post" name="form1">
 3         <center>用户名:<input type="text" id="username" size="32">
 4         <input type="button" onclick="checkUser(form1.username)" value="check"></center><br>
 5         <center>密码:<input type="password" id="pwd1" size="32"></center><br>
 6         <center>确认密码:<input type="password" id="pwd2"></center><br>
 7         <center>E-mail:<input type="text" id="email"></center><br>
 8         <center><input type="submit" value="register"></center><br>
 9     </form>
10     <center><div id="myDiv"></div></center>
11   </body>

3.checkUser页面验证信息:

 1 <% 
 2         String[] userList = {"baidu","taobao","qq"};//已注册的用户名用数组暂存
 3         String user = new String(request.getParameter("user").getBytes("ISO-8859-1"),"UTF-8");
 4         Arrays.sort(userList);
 5         int result=Arrays.binarySearch(userList, user);        
 6         if(result > -1){
 7             out.print("该用户已经被注册");
 8         }else{
 9             out.print("恭喜您,该用户没有注册");
10         }
11      %>

 

posted on 2013-10-17 20:21  李园春秋  阅读(1036)  评论(0编辑  收藏  举报

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