leetcode [223]Rectangle Area

Find the total area covered by two rectilinear rectangles in a 2D plane.

Each rectangle is defined by its bottom left corner and top right corner as shown in the figure.

Example:

Input: A = -3, B = 0, C = 3, D = 4, E = 0, F = -1, G = 9, H = 2
Output: 45

题目大意：

计算坐标轴中的面积大小。

解法：

计算两个长方形的面积，如果有重叠的部分，减去重叠部分的面积。我是分情况考虑的，但最后做出来发现忽略了很多情况，参考了网上的解法，这里计算重叠部分的面积很巧妙。

java:

class Solution {
    public int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) {
        int area1=(C-A)*(D-B),area2=(G-E)*(H-F);
        int left=Math.max(A,E);
        int right=Math.min(C,G);
        int bottom=Math.max(B,F);
        int top=Math.min(D,H);
        
        int overlap=0;
        if(left<right && bottom<top){
            overlap=(right-left)*(top-bottom);
        }
        return area1+area2-overlap;
    }
}